Introduction to Analytical Chemistry 11th Chemistry chapter 2 Part 6 @a2zpractical991

Hello, kids, how are you all doing? I think you must be having a lot of fun in your lives. I will definitely keep an eye on the Ray to Jet practicals. So, kids, let me tell you, kids, I'm going to explain Chapter No. 2 of Class 11 Chemistry, Introduction. I have started with analytical chemistry, and we are gradually approaching its final part. Hi, actually I've already completed about 5 parts of it. So today I have come with your Part No. 6, the introduction to Chapter No. 2, analytical chemistry So come on, kids, we're reading this chapter very carefully and seeing how What are the contents in part no. 6, since part no. 6 is very important for your exam? Liye. So let's quickly go through our Part No. 6 right here, and the first topic is "bachcha" which we We will study limiting reagents here, what will we study? Limiting reagents, limiting What are reagents? Carefully examine what a limiting reagent is, because often, many Children don't understand what limiting reagents are. You see, before we look at reactions from Waqera, we first observe them in our normal lives, Can we identify limiting reagents from our everyday life examples? Yes, we can identify them. It is possible. Alright, to make a cup of tea, you'll need sugar, water, and tea leaves. Lagega. If I leave you behind, come on, look here, see what's yours, yours here If there is sugar, you will put it in water; then, the sugar you take will be slightly less, and the water. What do you want, more people? Water log, a little more than usual, so what happened to your water, it became excessive for you Sugar, what happened to you? Sugar, you've become the limiting reagent, so listen carefully, Whatever amount I'll use in my reactions, or whatever thing I'll use a lot Less will be generated within our reactions, so that is our limiting reagent; what about that? Hey kid, limiting reagents—I think I've cleared up everyone's doubts, so let's go ahead. We are watching an animated video here; actually, we are looking at a photo, this photo What do you see here? Look, there are 4 sodium and 3 chlorine atoms, so one sodium One is going with chlorine, and the other is going with sodium. Hi, sodium is heading towards chlorine, so these two are moving toward each other. It is going, so 3 chlorine atoms are reacting with 3 sodium atoms to form 3 NaCl. Made it, look, an NACL, again here on the left, it's more, which means CL is less, so CL What happened to us, C L became ours, limiting reagents, and what happened to us, N A? Excess reagents, I think I've already clarified the main purification, so to clear up your doubt What is a limiting reagent and what is an excess reagent? For example, at home, at home If I'm making a solution with water, I'll add just a few drops—2 or 3—of nibu. I am using the amount of cheese in the reaction, so that is called the limiting reagent. and the water main is used a lot, so that is our excess reagents; I think this is the doubt. The child has now understood everything clearly, so let's look at the definition — the definition of a limiting reagent. What is called the limiting reagent is the one which gets consumed in the reaction. reagent, a reagent that is completely consumed in our reactions, then that one What do we call it? Limiting reagents. What will the child call it? Limiting reagents. Everyone's doubts are clear now, right? Let's see some reactions from us and observe them through that. What is the limiting reagent here, and why, in chemical reactions? You should know how to find the limiting reagent; in normal life, we've already done it, right? It's limiting, okay, well then, let me take some examples here and that example We'll see whether you can figure out limiting reagents or not, okay, come on Look, I took NO plus O2 here, so the formation of NO2, okay, NO2, balance this. If you're going to balance it, by how much will you balance it—by 2—and by how much will you balance it? Two, so, you see, yes, okay, now what happened to all this, balance is done Gaya, 2 nitrogen became, 2 nitrogen, 2, 2 not 4 oxygen, 2, 2 not 4 oxygen, like this You've given some reaction, so what kind of reactions do you see here among the normal ones, you? You can see in the normal SE reactions, that if you take NO, if you take NO, 2 moles How much O2 will it take for you, always 1 mole, how much O2 will it take for you, always One mole, I've taken normal reactions, where I'm realizing this, To produce NO2, you need 2 moles of NO, and comparatively, you need O. We'll have to do it, so let's see, now we'll do some things here in this question. You're mistaken, consider, considerer, what did we consider, what did we reject, that 8 moles are with us What is it? No, there isn't, no, there isn't, and 7 moles, 7 moles, what do we have here, O2, these two are together My reaction, creating NO2, then if I ask you, tell me, between these two, then you can determine which one is your limiting reagent and which one is your excess reagent. They will produce 8 moles of this, NO is not present, and there are 7 moles of O2, so 7 moles less Hi, that's why O2 became our limiting reagent; no, baby, you shouldn't do it like this. Look here, look very carefully, how I'm doing it here, very carefully Look here, come on, look, listen to this, look, what did he just say, the beginning of the reaction What we are realizing is that the compression of O2 has become double that of NO2. What has happened to NO2? It has doubled, but what is given in these questions here? Hi, 8 moles of NO are given, and how many moles of O2 are given to you? You've been given 7 moles of O2, so pay attention. If you follow the sunnah, your limitation here will become very clear; please observe carefully here, your The limiting reagent will be, look, whatever NO you have, it will be in double amount. If O2 is half of your amount, then it will be 8 moles, and how much is this? I've given 7 moles, so what can be inferred from this is that if there are 8 moles, then 8 moles If your NO is 8, what should O be? Half of 8 is 4, so what should it be? It should be 4, it should be 4, how much should it be, it should be 4, but here it is given as 7, so if we see, subtracting 7 from 4, we'll get 3, meaning 3 moles, what is O2 here, is it extra? What is given as 3 moles of O2, is it extra? Hua, toh O2 aapka kya ho jayega, excess reagent, aur ANO, ANO, jo ki 8 mole diya hua, What will happen to you, limiting reagent, if you don't understand, then look here, look, reactions Who knows what's happening, that with O2's competition, how much will remain for us, double the amount It will be half, meaning, if you take these 8, they should be exactly half, only then this Go there, what kind of reactions will there be, same same reactions will happen, meaning, if here it's 8 It will remain, so you'll need only 4 O2, that's all that's required to complete these reactions. For it, we were given what? We were given 8 moles of ANO, and 7 moles of O2 were provided. If I had 4, these reactions would balance out, but since I have 7, it's 8, so half of 8 How much is it, 4, like 2 is, then half of 2 is 1, so what is half of 8? It should be 4, it should give 4, if it gives 4, what would these two be, in a balanced way chemical reaction data, but instead of 4, we get 7, so what about 3 moles? It is, O2 has an excess here, then what will happen to your O2, will it become the excess reagent, what will happen to your O2? It will become the excess reagent, and as for ANO, it will become the limiting reagent here. This is a very serious matter, and what we have here is insufficient. You should conduct your own test. We can also do it on a book-wise basis, how it was derived, from 8 moles of reactant to product. For the bane, however many moles are being combined, do it that way, then you too will have it. I'll tell you the method, main, so listen carefully, to find out, 8 moles of ANO into, What is being formed here? 2 moles of ANO₂, product from reactant, 2 moles of ANO, meaning, 8 moles I was given ANO, which is being consumed; whose is it yours, in 2 moles of ANO2, and What is a reactant? 2 moles of ANO, okay, everyone understands, now, if you consider this You'll divide it, okay, you'll divide this, okay, this will cut it, this will cut it It will be cut, so how much will you get? 8 moles of ANO2, okay, let's look at the second one, Look at O2, then how will you handle O2? 7 moles of O2 multiplied by, in O2 what? It is being consumed, going directly into the product, so ANO₂, 2 moles of ANO₂, and 1 What is a mole, your O2, sorry, sorry, what happens to 1 mole of yours, O2, what should be done here It's the ratio of product to reactant, product to reactant, so how much product is there, 2 moles Year 2, or 1 mole, what is yours, O2, okay, then this will cancel out with this O2 O2 will be canceled out, 7 will remain, how much will remain, 14, 14 moles of what will remain here? 14 moles of what will happen, ANO2, okay, so O2, you're seeing O2, 14 moles, which is yours What is this, excess? And what is this, your 8 moles are coming? Okay, how much was the previous one? Rate mole, what will happen to you, limiting reagents, and what will happen to you, Excess reagents, that's right, so I've explained this to you chapter-wise, you can also do it this way You can do it, and above, I've already mentioned a clever trick; if you want, I can tell you that one too, plenty more You can do the following with limiting reagents and excess reagents: find out, determine, calculate Oh, after seeing the reaction, don't just write a reaction, check it, man, so, write one reaction Ka, his, and check it, dude, here, 2 moles are appearing, here, this one, absolutely It feels like 8 here, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here it feels like 4, then here 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The first question is which of these is your limiting reagent? What else did he ask? The collection of Udyta for the mess wagon. Asked, and at the end also asked is how much is left from your access resistance in the Indra reactance, it's also asked, okay, let's see the solution here. How to solve the problem step by step, carefully observe the solution here. First, we will remove the first reactance from the experimental nervous system. We'll eliminate the chaos of malls. The argument is about metal. So, how much will it amount to? 637.2 Graham and Molar mass What is the molar mass of ammonia? Calculate it. After nitrogen, the next element is oxygen, and the atomic number of hydrogen is one. 14-15-16-17 How much will it be? How much will it be? Carbie said he has 47, who has 37.4, 37.4, 37.4, malaan ki paadaa hai aamani a hai chay If you and Ashir are still here, the one who is kept, now from this very moment, we people What will happen, the next molayakhik and special you are all targeted to debug the ddiyokhsai Correct, the second seat is occupied by Vakini Krabhan, the caretaker of the car. You must calculate how much carbon is present in this compound. Find out the number of moles, which is 12. What is the molar mass of SiO₂, given that the atomic mass of silicon is 28, oxygen is 16, and carbon-12 is 12? How much will it be if 44 is added to 44? Correct, so? Molar mass of carbon dioxide is 44. Dividing it by 2, we get 25.9. So, this will be 25.9. I've removed the moles from both of them. What did I get out? In the first step, moles are removed. Now, we will see the second step. Step 2 Okay Step 2 We will find out that Look, so much ammonia is being used here. There is so much carbon dioxide. But you should know how much is being used here. This is the total mole I have taken. Let's calculate how much usage there is, let's keep going Now we will determine who has consumed how much in which one. 37.4 moles of ammonia are there in my possession What is Maulvi Saab? Ammonia, right, which is being consumed You must wear these shoes, they are essential, and we said so, it's a game. They were certainly necessary to carry on, so they were separate from the rest. I mean, it's slow here, 18.75 million is already quite a lot. After us, the common thing is usual for all of us. Go and get 34.4 ammonia slowly, it's harmful. What is the meaning of "Kshunan"? 18.75 ammonia is being diluted Let's also turn carbon dioxide into black ash. How much consumption is happening in the Indra Reactions? So, what is the total number of moles? 24.9 mol of C O Two Into Product Reacted What is the product we have? Voted divided by vote One mole of carbon dioxide Alright, everything is one and the same, so you'll divide it. So you're voting again, same 25.9 Maul of AF SO 2 So here it is 18.75 moles of What is Maula Pathan? Douring the reaction when the reaction starts there So, I've calculated how much molasses is being consumed. Tadiz, the into product, pan, reactive So come in access and what are these for us So the first phase of the awakening process, the thing that triggered the shift, was a single moment, even just a glimpse. He is near, the one who has the power to limit the flow of Peas, and there is a need to stop him from doing so. Vastir karen the jo aap haan gaddhi kani se wala hi rogion ka ROGIYO Diseases, the path of the unrighteous, I am a source of benefit, so those who do not go are new. As much as it is, that's all he can take. It's fine for reacting inside. If you understand what I'm saying, then Atin Point Seven-Five Moli is reacting here, but for making the paste, it's this much—25.9, which is not that much, really. It will be prepared; the rest will remain in our access, okay? So, tell me how many moles are being used. ATIN point seven five into molar mass of urea. What is the molar mass? It is 60. You will multiply it, and what will you get? What will it become? You'll understand everything here that I've said just this much mall, not that mall, this mall, Teacher's mall, only this much mall, in this reaction, our consumption is happening, okay? 25, meaning not that. Insecta is commenting, meaning the news is not for us, so if it's correct, your existence has already become CO2, which is not right. Hey, Bal Bhara, skills are coming, the anxious ones are watching, what's this? Is this the second bomb? Why is it hated? You know, your mass is coming in at 114.8—now let's move forward. Now we'll proceed further, and finally, we'll see what's happening with the farm. Yes, a massive excess resistance lift, an inward reaction. So, what do you have in the axis? Carbon dioxide, let's go, first target the Angara province, the month of May has already passed. You are warning us, why are you going there, why for swan, why again for the chela? The reactions, so I'm removing you, look here, how much excess reagent, how much excess reagent remains in the reaction, How much excess reagent is left in our reaction, okay, let's see. How much was used in total, 1142 grams, minus, how much CO2 is being consumed, How much is being consumed, 824.6? You will subtract this, and whatever answer you get will be your excess left in the reactions. So, listen carefully—here it will be 318.9 grams. Write down the moles, and the ratio of product to reactant; that's correct, so you'll get it. So, for these, the solution at the beginning is how many moles will you get? That ginger root has been dug up from a field on the internet. What's happening that I felt so bad about telling Kidbaya to Prestom? Are you working for the purpose of this task, and do it very carefully, and you must do it very carefully because you are responsible for your einako And if you work hard, only then will you be able to achieve all these things. You might feel discouraged, thinking, "This is impossible, it can't happen." But the truth is, you'll have to put in a lot of effort, and you won't even need to do so much, because I'm the one doing the studying. You will be able to do all these things only if you put in a lot of hard work; otherwise, you'll end up being an uneducated person, not someone who is studying. How can we calculate the PRAYJEC, and how can you extract it using your REMANE? weight percentage or mass percentage, those will be the first ones we'll cover, starting with our base It was a proof, mother's parting and I realized the percentage, so I thought and watched out what this is, what is the mass once this match percentage is half percentage. The west wind has risen, the urban states are damned, yet they remain happy, sir, ours In the solution, both the right and left sides are equal, and the large one is the same as the small one. Why do people come to you? If you're asking about mass percentage, Chondage NNN Therefore, Sreevap will be Neprai Maa Sarika What does hAPPLAUSE create? What is the use of a cooked mango? To stick, to adhere Has the package been documentos? Sometimes he used to become a show-off. Salvand when this is good Hello, Miss Bench, how much of your 18 grams has been taken? So, in other words, that will be your solvent, right? Let's go ahead then. So how much will this cost? 2 by 20, one minute, one minute I keep forgetting to write multiplied by 100 over and over again. What will you write after writing this here? Multiply by what 100? After writing this, what will you write? Multiply by what 100, okay You must definitely multiply by 100, don't forget, okay? Alright, now this whole thing Now, when you calculate all this, it will be correct, right? So this will be 0.1, 0.1 divided by that is 10. So how much will you get, 10% Alright, so calculate the mass percentage of the solute. So, the solute is 10% in the entire mixture and in the entire solution. The 2 grams you took, isn't it the solute? 18 grams of water Okay, so the child is understanding all these things. Please just leave one comment in the comment box to let me know Yes, sir, please explain the entire thing to me clearly so that I can understand the concept properly, okay? And definitely share it with your friends too, so that I feel even better I can make even more videos for you, okay, kid, so please study very carefully. You need to pay the tax for your practical today.