12th Physics Practical Activity 5 | Diffraction Patterns Using Laser Beam | Board Exam Practical

So today we are going to see the practical Activity No. 5 of the 12th Maharashtra Board diffraction pattern using a laser beam Here we will see what is being watched the laser beam from the screen's edge How will we diffract at different points? Okay, come here today, let's do the pad. Look, how does the setup work here now? I'll give you a screen. What are you saying here? Fix it by placing graph paper with L4 points. After that, we will use a laser here. we will use this diffraction grating what we also call the screen Yes, this laser light is not particular. points to bend are going to diffract You are the one who kills, not the one who can speak Okay, let me show you, exactly this way Keep the screen here, put it right here, one I've made a proper jugad here, after that just as I place it here, this one As you do it, so it is yours. You can see here different types of I get points, now separate these points individually It's called intensity, that's why there's so much of it here. Tell him to go to the center, Maxima, and her Primary maxima of the baaju wale and after that secondary maxima so this is the Center maxima, quite an intense look primary maxima and secondary maxima, it also comes here, here there is very much There's a small dot, you won't see it Oh, well then, take care, you know, you know We'll take a look, how do we take its reading now here Want to earn points Hey, do you have any points? They will appear here, okay, let's go Now I'll make some points here with this student. Like you, you or this secondary It's maximum, okay, even here like this primary maxima, and that is the secondary maxima, okay Now that I am making this laser light You will start seeing all these points displayed here. Hmm, now us What should be done, right here exactly The pattern you're seeing, like here, the pattern Here you can see it's written "distance," so what is distance? It's hot, I'll tell you the details right away, distance The distance that is yours, this on graph paper, the first screen here That's the distance, how much is the fee? 12 12.5 cm, to AB distance on 12.5 will be written, order 1 Order 1, I'm telling you the main thing, like I'm here If I had chosen this center, then from here to here It is distant, that is order 1, okay The distance from here to there is this. It's order 2, so 1, 2 are written here as per your input. after that, the distance between the central spot and the Five points, what is the value of L1, this is it This first number, starting from the center spot If this distance is calculated up to here, then I'll show you right now, that is the L1, and then you were asked L dash, from here to here If you've measured the distance, then L dash, After that, you have to calculate the mean, Divide this by 2, I It is possible, the value of 10 theta, L divided by 2 This will be your mean, L, and this will be yours. If you divide the distance between these two, you get L divided By 2, it will come back, 10 inverse, you'll get this The value of 10 is obtained. You will place the value of 10 here. If MATLAB is used on this side, it will become 10 inverse. You can see this in my previous practicals. The one I uploaded a year ago video me, description me main link Dunga, there is a very detailed explanation about it Hi, can you see it, just a quick one Revise it for you, in case you get it in the exam How can you do it in a very fast way? After that, a distance formula d is equal to n times lambda upon sin theta, this is the value you get have to calculate I won't show you any measurements. As you are stating the value of L1 and you L2, You must absolutely take these measures exactly like this It is, we will do it first We'll take it straight on the line, who was the maximum? The central maxima was that. if ever you, you It's coming down from above. If this remains fixed, the point goes up and down. If we can't find him probabilities, what will we do? Just a little bit of it We'll keep you in line, I've already put this in line. What can I do here from here? You can measure this point very accurately. Like, look, this Center SE Primary, that is yours L1, how much is it, 5 It's coming my way, and from the center too. How far are you going to measure this distance here? So, you'll become my L2 then. Alright, let's see. Your L1 starts from here to here. from here to here L will be there, after that take it from here Measured up to here, So for the second order, it will come here, The value will be obtained in MATLAB. from here onwards Your L dash will be achieved up to this point. I want to get rid of it, Find the value of 10. L divided by D What is yours, this means, divided by D, we will do it, the value of L divided by D will be obtained, D is equal to nL divided by sine theta to if you are involved in this calculation If there's doubt, then even now I'm doing the calculation. I can't see it, you're mine In the video from 1 year ago, the link will be in the description. You can see it from there,