if there's one thing that I ran out of
time inside the classroom it was
teaching the ambiguous case when we had
two solutions it's a lot of work and
that's a lot of step-by-step examples of
working through the problems to find all
the missing measures of not just one
triangle but two triangles well lucky
for you I found my top three examples of
me going through this concept inside the
classroom and I compiled them all
together into this one video just for
you I hope you enjoy so right now ladies
and gentlemen we're given 58° B = 12 .8
and AAL 11.4 all right so let's go and
draw the triangle like we would any
other
time so I could say here's a which is at
58° all right here's C and we'll call
this one b c we don't know any
information for B we know this is 12.8
and a we know is
11.4 right so automatically ladies and
gentlemen you can see that I have Sid
side angle all right when you have side
side angle rather than just following
your daily task that you do every single
day I kind of want your ears to perk up
and say all right now is a possibility
that I have two cases all right because
what we need to be able to do is there's
a possibility now that I could have
multiple triangles all right and here's
what here's the case the reason why this
isn't really a great um triangle I could
actually even shorten this up but what I
could uh what I'm trying to show you
guys is you could have a triangle that
looks like this right couldn't you also
just draw the same triangle
if you kind of use this as a
hinge and it went right there right
because we don't know what angle C is
right so my angle 11.4 could be here or
probably a little bit or we could say
11.4 is
here you guys see how that's a
possibility because we don't know what c
is right now all we know is what these
two side lengths are and yes I know my
triangle isn't written because this side
is much longer than this side and it's
shorter but we'll let get through that
but do you guys see how I could have two
possibilities
yes that's like me hinging like that's
pretending me like I took this like a
hinge on a door and I like I rotated it
down to here okay so it's kind of like
the pathway of that side so you guys can
see there's actually two triangles I
could have an OB I could have a triangle
with an obtuse C or I could have a
triangle with an acute C right so there
is a possibility so it's not as it's not
as basic as just hey give me money take
it back you know the stuff that we were
talking about before so there's a
possibility of two different triangles
there's also a
possibility what if 11.4 looked like
that and let's say you know here's this
side
length is it a possibility that these
could not even touch it is let's say if
11.4 is that long and then we end up
finding C because we don't know what the
length of C is what if C is short all
right we'll get through that case right
now um let's just go and take a look at
C I want you guys understand there's a
possibility of either two triangles one
triangle or no triangles and this is
always going to happen when we look at
our side side angle so how does that
work because Mr M what you just told us
to do is just find side side angle and
so forth or Define your missing angles
well let's take a look at it so we have
a ratio right we have a over a and we
have a side length B so let's create the
law of signs so we have
11.4 over the S of 58 degrees equals
12.8
over the S of
B so we do our same thing we do our
cross multiplication and we could say
that s of B is equal to
12.8 times the S of
58° all over
11.4 I'm solving for B so I mul I cross
multiplied and then I divide it by
11.4 so I can do 12.8 times the S of
58 and then divide by
11.4 so I could say the sign of B is
equal to
95 2
two all right now ladies and gentlemen
does that make sense for that to be an
angle right you got to take the inverse
sign correct right so you take take the
inverse sign of your second answer and
you get 72.2
1° so we say b equals sin inverse of
9.95 22 and we could say b equals
72.
21° okay so here's where it's going to
get a little
dicey so let's go back to the unit
circle all right what I did is I just
found the
inverse right I apply the inverse and
the important thing for you guys to
understand about the inverse is if I'm
going to look at let's say I have a sign
value let's look at the sign value
of2 if I
say the S of b equals 12 is there one
answer or two answers to that
there's two because what is what is is s
equal to 12 at pi over
6 yeah of course it
is and it's also equal over here
right so if I was going to say sin
inverse B of2 we could say b equal pi/ 6
and 5 pi/ 6 right because your sign is
positive in the first and second
quadrant so therefore there's two actual
answers we could say here it's pi/ 6
which is your reference angle notice
these are your reference angles but this
angle right here is 5 pi/ 6 right so
does everyone understand when I'm taking
the inverse of my sign I'm my domain I'm
going to have two values that are in the
first and second quadrant I have that I
have my original angle and also using it
as a reference angle so what I want you
understand is if I'm going to look at
72° where my mark toop go so if I'm
looking at 72° and I
say if I say the inverse of
95222 is giving me
72° which is right here do you think I'm
going to have another angle that's going
to have that exact same sign value yeah
I'm going to have the one over
here right so what would that angle be
how how could you we know this angle is
7221 how can I figure out what that
angle
is close not exactly 90 but if we take
180 minus that we'll get what this Ang
we'll get that we'll get the remaining
angle okay so let's go and take
um so let's go and take
180 minus our angle 72
21 and what that gives us is B is going
to could also
equal
10779 it's okay we're not done yet
yes what do you
mean this
one here no this from here to here is
72.2 1° so we want to find what that
angle is so we're taking 180 minusing
this and that's going to give us that
angle well I'm not done explaining I'm
still going to kind of go through it do
you kind of understand though how
there's two different angles that have
the same sign value okay do you
understand here how these both have the
same sign value2 and2 right so same
thing with this if I give you one angle
you know there's an opposite one that
has the same sign value right these two
angles are I don't know what their
coordinates are but they're going to
have the same sign value right so if you
find one you got to make sure you check
with the other one because there's going
to be two in the first and second
quadrant okay so you got to check two
angles we're going to go through now do
do both of these triangle do both of
these angles work so that's what we do
is we say we create case one and case
two so right now we have b equal
107° so we could say b equal
10779 de or we also said that b could
equal 72.2 1° so there's a possibility
now there being two different C values
and let's go and see if these
work okay so what we do is we write case
one case
two so case one says that um let's do
this as case one and this will be case
two so case one says this is 72. 21°
that's an acute angle right
so we could say that's going to look
something like
this
58° um that's going to be something like
this so this would be 72.
21
and there you go and this is oh
wait did I get them to be the same
what oh I wrote it in there didn't I
okay yeah we said that could be 72.2 one
or we could look at case two which says
it's GNA I wrote in I wrote in case
number one we don't know that that's one
example
right we don't we don't actually know
what this angle is right
now I wrote In what B was and I wrote In
what a okay we don't know what c is
though right now m let's go and take a
look at this one so if I say now um B is
equal to 102° so I still have
58° what you guys need to understand is
do do you understand when I was taking
well first of all we have side side
angle do you know in the other ones I
wasn't using the inverse sign right when
you when you complete the inverse sign
that's what's giving you your two
options
right because you have when you complete
the inverse sign you know that you have
to be able to find both values that's
why that's why I drw the unit circle
when you apply the inverse sign you have
to understand that there's going to be
two possibilities in that first and
second quadrant right that's why we come
up with this case
so what did I find a a b so we said B
could equal
17° all
right so now what I want to do is I want
to see do do either of these both
work I know it it's not
work so let's go and take a look at case
one does case one does this work if I'm
given A and B can I figure out what C is
so 180
minus
58° right we are we're given 58° from
the beginning and then minus our new
angle
72.2 is that going to give us our new
value equal to C so what will now angle
c equal right because on my case one I
figured out what B was and I now I can
figure what C was so we do
180 minus 58 minus 72. 21 and that gives
me yeah hey C is going to be 49
79
degrees
okay2 oh it's just
7.21 okay let me go and change it then
180 minus 58 oh I did it right I don't
know why I wrote that in
there all right so now that's for case
one what about if Case two what if we
said now hey this is going to be 170°
this is 58° is it still possible to
create this second triangle so what I do
for this C is I do 180 - 58° minus
10779 de equals c so we do
180 180 - 58 minus
10779 and guess what I get
14.21 so I could say 14 .21 de equals c
and I know my triangle is kind of
looking a little crazy guys but it'
probably just be something like that all
right so we could say this angle is
14.21 so do you guys see how I can
create kind of triangle here's where
it's obtuse here's where it's acute but
there's two possibilities and I can
still remain I can still create the same
so we know a is
11.4 B is 12.8
so the last um remaining value is we
need to figure out what our c is so
we're going to use a law of signs for
each value to find our value
C so for this one I don't know I'll use
uh a so I'll do
11.4 over the S of 58
equals um C over the S of 49.7 9 that's
for case one for case two I'll do the
same thing
11.4 over the S of
58°
equals c over the S of
14.21 all right and then I'll cross
multiply and divide I'm just going to
kind of do this to speed this along so
my last one uh for case one I'll do
11.4 times the s of
49.79 and then I'll divide that by the S
of 58 and I get
c equal
10.26 for this case I'm going to do 11.4
* the S of
14.21 and then divide that by the S of
58° and here I get C is going to equal
3.29 okay so ladies and gentlemen the
main important thing you guys need to
take from this all right I know it's a
lot of extra work you're looking at you
just need to take from this when you're
given side side angle and you have to
you have to apply the inverse sign
there's two opportunities you could have
an obtuse or you can have an acute
triangle you need to make sure you look
into both of them next what we're going
to do is look into what if there's no
triangle at all all right and that'll be
pretty simple that you guys will be able
to see okay so in this problem what I
have is a = 60° a = 9 and C
10 so what I'll do is I'll just create a
triangle here kind of see what it looks
like
60° AAL 9 we'll say here's B here's c um
so C is going to be 10 all right now so
what we first want to do uh with this
problem is obviously go ahead and take a
look at um what what our uh use our law
signs to be able to figure out what the
angle of C is going to be so I have 9
over the S of 60 equals 10 over the or
10 over the S of C so everybody can get
to this point right Elizabeth yes okay
it's pretty basic and then we can solve
for the S of C so we could say the S of
C equals uh 10 * the S of 60
by
9 what form
how we'll go through on this part of
thing I know right how do they figure
out that like
MC so now you're just going to take the
S of 60 times it
by times it by
10 divid by 9 and what you have and then
you take the inverse sign of that value
sorry so you have S of C equals let me
do this again for you 60 sin * 10 / 9
you're going to get C =
96
2250 okay now to find what C is you C
equals sin inverse of9 62250
does everybody understand that to find
the angles you have to apply
them yeah that's what you supposed to do
even on your homework last
night now I do the inverse of that and I
say C equals
74.2 uh
1 okay so now I have Cal 74.2 1 degrees
but ladies and gentlemen this is getting
a little bit more difficult than just
doing this one problem so what you're
going to look at is all right it could
be 74.2 but what I want you guys to
understand is let's go back to our unit
circle let's look at two angles let's
look at pi/
6 and let's look at 5 pi over
6 all right now notice the reference
angle these are both pi over 6 off of
the xais right right now let's take a
look at our coordinate points this is 3
over2 comma 12 this is 3 over2 comma 1/2
what do you guys notice do you notice
that for each of these angles pi/ 6 and
5 pi over 6 they the sign is exactly the
same
correct right sign is exactly the same
so when you're finding the inverse of of
an if you're finding the inverse of a
value you could possibly for sign you
have two positive answers so there's
might be two Positive Solutions so let's
go and take a look then of what would be
if this is 74 what could be a possible
other solution so to find that I could
say C =
180-
74
21 again what I'm doing is I'm taking
180
subtracting my set my angle to be able
to find the other possible
angle we're going to get to that in just
a second so I add 180 so one we take 180
and that's going to
equal
10579 so what I'm trying to tell you
guys if you look at take this take this
for example if you guys take the sign of
7421 okay so
7421 sign it's
9622 then attention teachers take the
sign all remaining Juniors who have not
been screened for VIs vision screening
may go to the media center this time
again all remaining Juniors who have not
been screened for vision screening may
go to the media center this time thank
you okay so what I'm trying to say
ladies and gentlemen is when you take
the inverse sign there's two possible
answers you could have 74.2 1° or you
could have
105.7 n° if you want to check that take
the sign of 105.9 or 79 you're going to
get n6225
take the sign of 74.2 you're going to
get
n6225 why do they same work because
exactly what I said here what's the sign
of pi/ 6 12 what's the sign of 5 pi over
62 so they both have the same value
right now we're just dealing with some
decimals and some angles that are not
the same but now we have 74° so we're
saying the sign of 74° is exactly the
same as the sign of
105° does that kind of make sense so we
need to make sure we both Solutions and
now we got to see can both answers work
can both of those answers work
yes so it's because your calculator is
just going to give you that positive
solution it's not going to work with the
reference angle of the other one okay
because it's not going to give you both
Solutions it's just going to give you
that one pos smallest solution well what
it's doing it's just giving you the
really the reference angle solution for
there so so now we have two possible
solutions yes um so the P 6 and P were
just an example they didn't they don't
have anything to do with the problem no
I was just kind of showing you why when
signs equal to each other I was like
where did you get that okay so now let's
just make sure that these two problems
work so let's do case number
one so if I said case number one I'm
saying a equals
60 and then I could say C equals
74.2 so therefore what does B have to
equal
well it equals
what well let's just do 180 minus 74. 21
minus 60 and equals 45 he said
what well no b equals
4.79 that's case number one if we did
case number two what we're saying for
case number two a still equals
60° but now I'm saying C rather cuz
remember C could be 74 or it could be
105 it could be either one so let's say
what if C equals
10579 de then what would b equal well
let's see if this will work so I could
do 180 minus 105.7
n° minus 60 therefore in this case C is
going to equal 14.21 these are all
degrees
okay so first of all the thing you guys
need to understand is we can have
multiple answers for
C right because our signs is exactly the
same then what I do is I just subtracted
these from 180 so if sign if C is
74.2 that means B is 45.7 n if C is
105.7 n that means C is 14.21 De all
right so let's go back and let's take a
look C for this triangle does that kind
of make sense well if this is 60° and
then I could say C is going to be
7421 and then B is 45° all right so I
didn't draw my triangle perfect but you
guys kind of have an idea it kind of
looks similar similar right let's go and
take a look at so that's case number
one let's go and take a look at case
number two what would a triangle look
like if what would my triangle look like
if I still had a was
60° um but now my C is 14 but now um or
my
B but now B is 14.5 and C is going to be
105° so let's pretend it's going to be
something bigger like
105° so now it's 105 degrees and we'll
call C kind of something like
that why are you changing
here I
mean all you need to understand is this
could be a here let's say that's 60
right then it could look something like
that okay so this is
105° and then this is
14.21 so you have
C A and B do you guys see how these are
exactly the same triangles but now
rather than having C be
74.2 now it's a obtuse angle so it's
going to be greater than 90 so it's
going to be like 105° so therefore your
B is obviously has to be smaller but you
guys see how there's two I know I like
my triangles aren't like just shape or
form but you guys can see how there's
two possible solutions there's two cases
so this is case
number case number two in case number
two we're saying a = 60° C = 10579
and b equal
14.21 so when we have two cases there's
two possible solutions what we need to
do is now find the rest of the
information for both of them so when we
look at this one um we're given we
already know what a is but we don't know
what b or what C are so we need to use
the law of signs again so I can just use
um a over s of
60° equals uh we're going to have sorry
that's 9 sorry 9 over s of 60 is going
to equal B over yes we TR find the
remaining angles we don't know what B is
and we but we know what 10 is or we know
C equals 10 right why can't we do the
yeah why can't we can't use the
Pythagorean theorem unless you have a
right triangle right so that's why you
have to go back using the law of signs
yes so are we trying to find the last of
no we well we we found when we found C
we found there's two possible answers
for C it could be
7421 or it could be 105 there's two
possible answers for it all right so
then if there's two possible answers
that means your third angle is also
going to be
different
okay yeah because look it you can see I
can re I can draw a triangle with a and
60 B are a being
nine B being or C being 10 but them
being but them with having the same
angles but within the same sides but
just one being an obtuse angle and then
one being an acute Okay so it's possible
for me to draw a triangle with an acute
and an obtuse but with the same
information up given that's what I said
when you guys have a side side angle
there's three options I showed you when
there's no triangle that can be formed
we did last class Peri we worked on ones
where there's only one triangle forms
and today we're working we're seeing
when there's two triangles can be formed
all right so now the only last remaining
information I don't know is what B is so
I just go and solve for b so b
equals 9 * s of
45.7 / the S of 60° and then here I need
to figure out what B is so I could use
either the same Ratio or I could use a
different ratio um let's just use a
ratio for our C so I could do 10 over
the S of
105°
equals B over the S of
14.21 notice how sign of B is different
in for each one of these so therefore in
this case b equals 10 * s of
14.21 / the S of
105° so let's go and figure out what
each value of B is because for each
triangle B is going to be different so I
have 4
5.7 s *
9
/ 60 sign and I get in this
case b is equal to
7.4
4 okay so for in this triangle in case
number one I say
7.44 and let's let's look at it does
that kind of make sense well at 60° my
side length is N9 right at 74° my side
length is 10 so if my angle B is smaller
than all three all those other two
angles then length B should be smaller
than right does that kind of make a
little sense okay so now if I give an
angle
14.21 do you think my new B is going to
be larger or smaller than
7.44 should be smaller so let's go and
take a look see if we did the math
correctly so I do
14.21 um s of that * 10
divid
by 105 sign and I get b equals
2541 and there you go there's two
possible
answers uh we notice here is whenever
you guys are given the information
before you even try doing anything let's
go ahead and sketch a picture right and
we can all do this no matter what we're
doing because you're going to be given
information and what we have to do is of
identify so let's just sketch the
triangle now again we can assume that
this is an acute oblique triangle
meaning all acute
angles but we know there could be an
issue here
is 68 that's going to be 18 a would be
19 okay but we know that if in when we
have the case of our um our ambiguous
case we could have an issue with that
being um we could have an issue with
this being it could be an obtuse
triangle as well right and we'll and we
we'll look at that uh when that comes up
however based on this information we see
that we have uh angle side side so it is
the ambiguous case meaning we could have
information that doesn't even create a
triangle we could have just this one
triangle that I drew up there or we
could have two possible triangles and
again I'll REO over that again as we get
to it but the first thing is we could
all just sell for a right here a we can
just least solve for a okay um so again
to solve for a we're going to want to
use the law of signs and we're going to
want to make sure a is in the numerator
so I'll say s of a over a is equal
to we have the ratio of C so that'd be
the S of
68° all over
18 and again we've already worked on
this last class period so I'm just going
to write this next one to solve for a
oops I'm sorry we know what a is which
is 19 so therefore a equals sin
inverse
of um AAL sin inverse of 19 * the S of
68° all over 18 now do you guys need me
to show you again how to do that on the
calculator or can I just type it in and
figure the answer and you guys can
verify with me is that how works
okay so let's go ahead and type that
into our
calculator you can type it all at one
time um just be careful when you guys
are typing stuff in make sure you're
using your parenthesis so make sure it's
already make sure your calculator is
already in degree mode so I have um sign
and if you guys didn't already get
calculators you guys can grab on the
back if you want to verify your stuff
with me instead of walking right in
front of the video camera but that's
okay so we have sine of
68 divid 18 *
19 and then we do sin
inverse and I am getting a equals 78.1
15 let's round this to the nearest
thousandth now the next thing we'll want
to go ahead and do is uh we're going to
want to store this answer okay we're not
going to want to use uh you know we can
use this as our final like we can use
this angle as our answer but we want to
make sure we store a so I'm going to go
and get store and then I'm going to so
stow and then I'm going to hit Alpha a
and again when I go over the next Pro I
can show you guys this again but we'll
have go ahead and store Alpha a
okay
now do you guys want to finish solving
this and then check for the second
triangle or yeah let's go and finish
this let's just go and finish this the
next one we got to find B so to find
angle B we know that all the angles in a
triangle add up to 180 so to find angle
B all I'm going to do is say 180° minus
my stored angle a minus
68 so that's why we like storing it
because we don't have to retype the
problem again so we do 180 minus Alpha a
minus
68° and I get
here
33
848 that means I stored it in my calcul
so I'm going to store that answer as
angle b as well so that's going to be
33848
okay yes no maybe so good okay now the
next thing though guys is we need to
solve for like little B right so if
we're going to finish this we got to go
ah aead and solve for little B so
therefore I can use a law of signs um
again and now I'm going to solve for b
but I'm going to want to make sure B is
in the denominator and when I'm solving
on this
example um what I'm solving in this
case we're going to want to have B in
the uh numerator because that's what I'm
solving for over s of B which is stored
in my calculator equal now again we
could use a A or C over C but since c um
was given to us C and Big C was given to
us that's what I'm going to
use now go ahead and solve in for b b
equals the sign of stored B time 18 over
the S of
68° so we go ahead and type that into
our calculator s of stored
B * 18
/ the S of
68 and I get
6657 we'll round
that all right now it's important that
once we do this we want to check using
kind of the hinge
theorem of geometry to make sure that
does the smallest angle have the
smallest side and does the largest angle
have the largest side does this kind of
work yes yes it does work right okay so
now we've kind of solved for this one
but what if my question was saying hey
is there one two or no triangles right
is there another triangle that works we
know that no we know that it makes a
triangle because we're able to confirm
it if we did this first sign inverse and
we got an err then we know the problem
there would be no triangle exists like
the information provided does not create
a triangle that happens when you guys
have that err off the bat um but in this
case we know one triangle exists what
about a second triangle so again we got
to understand guys what is happening
with sin
inverse when we're doing sin inverse our
calculator so we're doing the sign
inverse of or here's our angle a is 78
Dees 78 degrees is right
here let's just round it to 78° okay now
if we were to think about that like on
the unit
circle is there another angle where you
take the sign of that angle you're going
to have the same y-coordinates
wait where did you get 78 from that's
the angle that we found a okay right and
I'm just rounding it for easy ease of
use w't you guys agree that these two
angles have the same y-coordinate or at
least they're supposed to if I drew them
correctly right now so that means now
what exactly is this angle though like
that's the reference angle so what is
this
angle it'll be
the like huh what is that angle what is
that measure of that
angle 102 right because 78 and 78 and
this angle 102 are
supplementary so all if I got to do now
again let's we come back to this in a
second you would you guys agree that the
S of 78° is equal to the S of
102° would you say that their
y-coordinate is exactly the same yes yes
right yes
oh well why don't you guys say
something
so maybe let's make sure I didn't oh I
didn't store my B oops no wonder so 180
let me make sure my Alpha a is
correct sorry about that I didn't store
big
b s of alpha
B what' you
get what is your B B is
okay and then s of B so the S of alpha
btimes
18 did you guys divide it by S of
68 okay there we go I don't know what I
typed in wrong thank you oh good
catch so that's
10.8 13
okay now let's go back to the second
case you guys agree that the S of 70
degrees and S of 102 is the same right
now here's the problem when you guys do
sin inverse which we did over here when
you do sin inverse your graphing
calculator is only going to give you s
78° it's not going to give you 102° even
though the sign of those two angles is
is the same why does it only give you
that one angle because again remember
the inverse function is restricted it's
only going to give you that angle in the
first quadrant or the fourth quadrant
right it only gives you that positive or
the negative right here it's not going
to give you the obtuse angle however is
it possible that our triangle our our
triangle that we create could have an
angle of 78° or it could also have an
angle of 102 is it just
possible yeah those are both angles that
could be a possibility so what we need
to do is sense the acute or the obtuse
angle have the same sign sin inverse
only gives you the acute so we have to
check the obus so what we're going to do
is we're going to call this
A2 so it's really A2 of our second case
so I'm just going to call this my case
number
two so we solved case number one now
we're going to work on case number two
so what I'm what we mean by case number
two is we have the exact same
triangle this is still
68° this is still 19 this is still
18 but a we're going to say is now
obtuse because could a be obtuse as well
as be acute it could and let's see what
it is so now rather than rather than um
simple rather than estimating we don't
want to do that we want to take
180° minus a that we stored and we're
going to store that as or we're going to
figure out that value so now I'm going
to do
180 minus Alpha
a and I get 101.8
448 so does TH could this be a
possibility could that angle be 1. 1848
and then have
68° yes it works right now so that means
this example has two triangles however
let's just pretend what if what if this
angle ended up being like
150° is it possible to have 150 plus 68
no so therefore only one triangle would
exist so even though you could test the
obtuse angle it wouldn't create another
triangle but in this example two
triangles can be created all right so I
am going to store this as my new
a so I'm just going to take this new
answer and I'm going to store that as my
new a so store Alpha a okay so now Alpha
a is 101. 848 4628 don't want to use the
rounded answer make sure you use the
whole answer um so now I need to figure
out a new B right so we're going to say
B2
so what would B2 be well B2 is
180° minus my new stored a minus 68
degrees right you guys agree with me on
that hopefully so we do 180 minus stored
a minus
68 and I'm getting
10152 if I round it and I'm going to
call that my new stored B so now I'm
going to store that as Alpha B
are you guys okay with the storing and
everything do you guys want me to go
back over that next problem yeah sure
okay so now we have a and we found B so
the only thing I need to
check is small B now again since we're
solving for small B we're going to put
small B in in the numerator here so I'll
have B over the S of stored b equals
let's again use C which is
18 over the S of
68° so therefore b equals the S of my
new stored B * 18 over the S of
68° so it's really the same thing I did
way over here it's just with new B's
though right so I do s of alpha
B *
18 ID the S of 68
and I am getting b equal
3.42 and does it make sense guys for B
to be kind of small in this
example right because look how small
that angle had to be right so a really
small angle is going to produce a really
small side right which is different than
this one but this one made sense and so
does this triangle make
sense Yes No Maybe So
Okay and there you go