@a2zpractical991 đ HydroborationâOxidation of Alkenes | Class 11th & 12th Chemistry
In this lecture, we will understand the HydroborationâOxidation reaction of alkenes in simple language, with a step-by-step explanation of the reaction mechanism and important concepts for board examinations.
đ§Ș Topics Covered:
What is HydroborationâOxidation?
Reaction of alkenes with diborane (BâHâ) or BHâ
Oxidation using HâOâ/OHâ»
Anti-Markovnikov addition rule
Formation of alcohols from alkenes
Reaction mechanism and solved examples
Important questions for Class 11th & 12th Chemistry
â Important Concept: Hydroborationâoxidation converts an alkene into an alcohol, with the âOH group generally attaching to the less substituted carbon. The addition of H and OH occurs by syn addition.
đŻ This video is useful for Maharashtra State Board HSC students and anyone preparing for organic chemistry examinations.
đ Subscribe to A2ZPracticals for more Chemistry concepts, practical experiments, viva questions, and board exam preparation.
đ Like, Share and Comment if this lecture helps you understand the reaction!
This video explains the process of hydroboration-oxidation, a chemical reaction used to convert unsaturated alkenes into primary alcohols. The instructor details the mechanism using diborane ($\\text{B}_2\\text{H}_6$), emphasizing the Anti-Markovnikov addition of boron and hydrogen across the double bond, followed by oxidation to yield the final alcohol product.
So, children, today we are going to see hydroboration
What does oxidation of alkyls basically mean in hydroboration?
is that your alkyne, unsaturated meaning double
The bonded child becomes your primary.
Alcohol is fine, even examples of secondary alcohol
Yes, but first let's look at primary alcohols.
How alkyne is converted, explained
In Gaya hydroboration, the first of all children we have one
Unsaturated alkynes will not take unsaturated alkynes
An alkyne having an odd number of carbon atoms, then
Come on, today I'll tell you something, so pay attention carefully.
Look, all the children will pay attention carefully, okay? I've got it.
So, taking an example like that, it's BH3.
BH double bound BH2 OK and I'll handle this
Hydroboration Borane Hydroboration formula
It is B2H6, okay. Now listen carefully to this.
Your eyes are not fully open to understand the mechanism.
You should be here to do this. Come on, come here today.
Look, all the children, in B2H6 there are two molecules.
BS Tree and BS Tree's Tik A BS Tree BS
So, B2H6 will become six, okay, I'll write it down too,
There are two molecules of this kind, BH3, BH3; let me tell you about one.
You'll understand the rest when I start balancing.
Alright, now what happens, kid?
According to Boretty's calculation, it's two in the anti.
Marconicoff knows this thing.
Does anyone know about Antimarkonites?
Marconicon's rule, let me tell you what happens here
Child
Double powdered carbon carries fewer hydrogen atoms. Correct.
The partially negative charge goes to the doubly bonded.
Carbon carry more number of hydrogen atoms, right? So, check it out.
Here, the carbon that has a double bond is this carbon, and it has
The greater the number of hydrogen atoms, the more negative the part
Where will the child go? The child will go near this carbon.
All the work, it will be clear to everyone, you will say, sir, from this
It will become negative, so let's go with electronegativity.
If you go from left to right according to the property,
Electronegativity increases, hydrogen initially appears
It's known to everyone, and later you become the boron.
It's done, it will go, that boron is your partial negative.
It will be and hydrogen, what will happen to your partial positive now
Where will the child/remains who will beć è〠the negative part go? Double-bonded
Carbon can bond with a greater number of hydrogen atoms. Okay, okay, send it over.
If I send this here, if
When I send this here, the child shifts this bond over here.
It will become clear, alright, so this should look something like this here
Write it down
I'm fine, okay, just keep an eye on it. See, attach it here, I'll attach it right here.
That's possible, okay. Let me attach it here, PStwo, okay? This is single.
It will become PS, this will become PSTwo, okay, now the child
The bond here was a double bond; it has shifted here.
It's done, minus minus, what is this, look here, this, this
Negative is positive, so if H comes out, then the child would be
H had come out positive, that one near the minus sign.
What will happen to A? It will connect. Then, what will happen to one H? It will become two Hs.
So it could also happen here, so it could also happen here, meaning you
Here are three molecules, let's take one more molecule
I'll tell you the reactionâthis happens when it's negative, negative, from the firecracker, where?
It will become connected, yes, the doubly bonded carbon carries,
more hydrogen atoms
Right next to the atom, okay? Alright? Alright, kid, look hereâthis is the very essence of positivity.
The property will be very good, so it's due to the vote.
The entire electron in the inductor will be polarized on this side.
Alright, clear enough. Let's go, let's go. Look, now I'm writing.
I'm the one who likes B2 to single bond B2, okay, that's right.
That's where I subscribe.
The one who came out as plus is this, this is mine.
It's taking the electron here.
Subscribe to
Exactly for you
Shows the formula written out
Hmm, look how I am
It would have gone here now
Your Boron will connect. Connecting your Boron.
Okay, boron, how much time is it? It's two o'clock, okay? So I
Here, look, I'll write something like this for two times its
Check the balance; balance it with two and balance it with three.
So, look, this 3 2 go 6, this has become like molecules in time, 6
It has become time as a reactant, and the balance has become 6 times.
And I also need to balance 2 boron, so I've put it here
2 written, then 2 boron, what happened to my balance? It's balanced now.
Everyone got it, okay sir, everyone got it, brother
Is it dangerous? Okay, let's see what's next.
What did I say, kid? It doesn't convert into a primary alcohol.
Converts it into a primary alcohol
To convert a primary alcohol
apply certain reagents or catalysts
We will apply the reactant, sorry
What will this be like H2O2
H2O2 in the presence of KOH
Everyone will know how H2O2 breaks down now.
Yes, OH
There will be a break in 2 OH, okay? Now listen carefully.
That would be your modal number, and this is the number off.
Molecular has become three molecules here, please.
Molecules, you must know, right? Look, what is this? Look, what is this B?
The charge above boron is a plus 3 charge.
And what is above OH, minus one
Then the child will take a boron 3 OH from here.
How many OH will it take? It will take 3 OH.
So I'll have to balance this with 3.
Who will have to balance it, 3?
Look, I'm just writing it by breaking down 1 OH, H2O2
There's no need to worry too much; it's fine here.
Look, what will B do?
Reacting with 3 OH groups
What will be made here? Listen carefully.
What are you going to make here? OK, tell me what you're going to make?
Like B(OH)â, okay, these three have gone, now this one here
There are 3 OHs, kid, these will be substituted here.
So what will remain for you, listen carefully, what will remain for you, 3 times, 3 times,
Here will be your OH, this OH is so much time here
three times, what can you say about this propanol
Propanol, okay, so on the primary carbon you're looking at the alcohol
It becomes a simple reaction for the child to scare you
There's no need for it to be, what is it that you have, your alkene?
Meaning, unsaturated alkene is correct. In it, you have primary
Which alcohol is primary?
It will be necessary to react with reaction if B2H6 is used as
hydroboration, correct, just like hydroboration
If you do it, go 3-2; then this will also balance out twice.
The 3-time molecule has also become balanced; after that, you don't need to do anything.
Reacting with H2O2 and KOH
That is the peroxide.
Alright, this needs to be taken 3 times because there are that many molecules.
And boron also has a +3 charge on top.
So, OH has a minus 1 charge above it.
Reacting with 1 B 3 OH
It will produce B(OH)â, correct?
And it has already been prepared right here.
Your primary alcohol is left.
Just like this simple chemistry experiment
Or to study chemistry lectures
Follow up on the 8-8 practicals
Don't forget, thank you