Can you calculate the volume of this water tank? In this maths challenge, we explore how to find the volume of a cylindrical tank using the dimensions shown in the diagram.
Watch as we break down the problem step by step, identify the important measurements, and apply the correct volume formula to work towards the answer.
This lesson is useful for students learning volume of a cylinder, volume of composite solids, geometry, mensuration, and real-life maths problems.
**Before watching the solution, pause the video and try to solve the question yourself!**
Topics covered:
* How to calculate the volume of a cylinder * Volume of a cylindrical water tank * Applying volume formulas to real-life problems * Understanding dimensions in geometry * Step-by-step maths problem-solving
Subscribe to JJ online maths class for clear maths explanations, challenging questions, useful maths tricks, and lessons designed to make mathematics easier to understand.
If you enjoy the lesson, like the video and share it with someone who is learning maths.
This video provides a step-by-step mathematical tutorial on calculating the volume of water in a partially filled horizontal cylindrical tank. The instructor demonstrates how to find the area of the water's cross-section by combining the areas of a triangle and a circular sector, then multiplying that total area by the tank's length.
Let's find the volume of what we have on the board.
Welcome back to my channel. So, this is not easy at all.
Now, but we can do it together.
First thing first, the volume of a cylinder.
The volume of a cylinder is equal to area of the base,
area of base multiplied by the height. Okay?
Area of the base multiplied by the height.
And our base is a circle, right?
therefore the volume of this particular shape will
be equal to area of this circle but the problem
we have here is that we are not going to make use of the whole circle
because the water in this tank
is not full right and that is where we need
to be careful how we go about it since the water is not
full the area of this particular shape will
be equal to the area of the the part that is filled
with water right of the circle
or of the tank multiplied by the height of the tank the height
of the tank is 10 okay so this is where we are going
to concentrate on because once we are able
to get the area of this particular circle
the shaded part of this circle we just multiply it
by 10 to get our answer now this is the circle i want
to draw it bigger and we have this this is
the center of the circle and the radius of the circle
is four but the height of the water is six
the height of the water is six um what we
are going to do here is basically to try to divide
this circle into two shapes that we can actually find
its area this is what i mean because from
here to here is four it means that from here to here we
also before the radius of the circle
from here to here we also before the radius
of the circle please subscribe to the channel turn
on your notification bell
if this is the first time you're coming across this channel hit the
subscription button and give us a like
if you actually love what we are doing thank you very
much so at this point remember that from here to here is six right
so it means that the height
of our triangle will be height of the triangle will
be equal to six minus four which is two
so that means from here to here is two
and remember that this is a chord right this particular line
from the center to this place if we call this place
a b a b is a chord right so whenever you
draw a perpendicular from the center
to the chord you have to get 90 degrees at this point of
intersection and if that is so if we call
the point of intersection n it simply means that
let the center be O. It simply means that triangle
OBN or ONB
is a right angle, right? And if it's a right angle
triangle, it's
a right angled triangle. Now, if
that is the case, that means that we can use the Pythagorean theorem
to get NB, okay? So, this is
what we have there, like this. This is 4, this
is 2 this is n b okay remember that this is our drawing
and as a result of that i will not be able
to use this side of the board
so we are going to manage what we have here therefore to get
np is going to be nb squared let's call nbx
so we have x squared plus two squared using
pythagorean theorem we give us four squared okay x
squared plus two squared we give us four squared
Therefore, x squared will be 4 squared minus 2 squared.
So x squared will be 4 squared is 16, 2 squared is 4.
So x squared is 12.
That means x is square root of 12.
Okay, if x is square root of 12,
remember that 12 can be written
as 4 multiplied by 2.
So we have square root of 4 multiplied by 2,
which is, sorry, 4 multiplied by 3, rather.
4 multiplied by 3.
And this should be equal to square root of 4 multiplied
by square root of 3, which will give us 2 root 3.
That means that NB is 2 root 3.
So we have 2 root 3.
But we need AB, the whole base of the triangle.
So, this implies that AB is equal
to 2 multiplied by 2 root 3.
And this will give us 4 root 3.
So, we have that our AB is 4 root 3, right?
So, we are going to write it some way, that AB is 4 root 3.
Alright, now why is this important?
We need to find the area of this triangle, okay?
So, to find the area
of the triangle, okay,
Now, area of the triangle
is half base times height, right?
So, we should be able to have multiplied by our base is AB.
And AB is 4 root 3.
So, we have 4 root 3.
Multiplied by the height is just 2.
So, if we solve this, we have that the area of
the triangle is equal to 4 root 3 square units.
4 root 3 square units.
So, we are going to write this somewhere.
Area of triangle, 4 root 3.
Okay.
Now, remember that our intention
is to find the area of this place, right?
The shaded portion, which is from this triangle, this side.
And you can see that this is what?
This is a sector.
This is a sector of a circle.
This part is a sector of a circle.
So, the area of the whole part that we are looking for,
the area of this whole portion of the circle
is going to be area of the triangle plus area of the
sector okay area of the triangle plus area of the sector
and we have found the area of the triangle
and we need to find the area of the sector
to find the area of the sector let's recall
the formula for finding area
of a sector okay now area
of a sector is theta over 360
times pi r squared whereby theta is the angle here
the angle we have here is our theta so let
me clean this so the whole of this is our theta right
so theta over 360 times pi r squared now
let's also use this triangle to find the angle here
so that we subtract it from 360 to get our
theta so going back to our triangle let's pick half of it again
so we have four here we have
two here i remember that from here to here
is two root three right two root three now let's get this
let's call this alpha now this particular angle here can
be gotten using our trigonometric ratio
right so i want to make use of this side
and this side this side is our adjacent this side is our
hypotenuse, right? So, adjacent over hypotenuse is cos.
So, we are going to have that cos alpha is equal
to 2 divided by 4, which is half.
And we know that cos alpha, that means that alpha
is what? 60 degrees because cos 60 is half, which is
0.5. So, this implies that alpha is 60 degrees.
So, if this place is 60 degrees, that means
we have 60 here and we have another 60 here
so all together here we have 120 right and if we have
120 here that means our theta will be 360 minus 120
which is 240 very important so that means this
place is 240 degrees 240 degrees now that we have found
the angle we can now use our formula to find
the area of the sector
so now let's solve the area
of the sector area
of the sector now will
be equal to our theta is 240 divided
by 360 multiplied by pi times r squared that is
four squared so it will be equal to let's cancel zeros right
and 24 what can go into 24 i'm going
to take 6 and same time 6. 6 into 24 is 4 and 6 into 36 is 6.
2 into 4 is 2. 2 into 6 is 3. So now we have
2 over 3 times pi times 4 squared is 16.
Now if we solve further, we are going to have this to be
2 over 3. Okay. Now 16 times 2 is 32.
So we have 32 pi over 3. Now this is the area of the sector.
This is the area of the sector.
So, let's write it somewhere.
So, area of sector is equal
to 32 pi divided by 3.
Now, remember that the area of this whole place now,
all this shaded portion, right?
The whole of this shaded portion from here is going
to be equal to area of the triangle plus area of the sector.
Okay?
So, that will give us the area of the portion that contains the water.
so let's go ahead and find it
so this shaded portion now area
of this shaded portion which
is this will be area of the triangle
which is 4 root 3 plus area of the area of the sector
which is 32 pi over 3 now we are multiplying this by the height
which is 10 so this will give us
the volume of this tank right
so the volume will be equal to now if we solve this you're going to
have 40 root 3 if we open the bracket plus
this will give us 320 pi divided by 3 so if we solve
this further 40 root 3 if you press
that in your calculator you're going to get 69.3 so we have
69.3 plus now 320 pi divided by 3 we give us
335.1 now some will be saying how did this
man get this i've already punched that in my calculator i'm
not an alien okay so this is what
you're going to get and then you add these both
if you add both you're going to get 404.4
square units oh sorry volume cube units okay
cubed now this is what you're going to get as
the answer 404.4 um units cubed so thank you
so much for watching and see you in my next video bye