#MathUnusual | How can Integrate ?

MindRiddlex
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4 Video Views·Sep 12, 2026
How can Integrate?
Mathematics, Integration, IIT JEE Main,
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Video Summary
AI GeneratedThis video provides a step-by-step mathematical derivation to solve the integral of $\\sin(5x/2) / \\sin(x/2)$. The instructor demonstrates how to transform the expression using trigonometric identities to simplify the integrand into a form that can be easily integrated.
integration sine 5x by 2 divided by sine x by 2 dx. How can we solve this problem? Can we simplify
the function? No, because it is already in simplified form. Can we use any trigonometric
formula? No, because we don't have any trigonometric formula for sine 5x by 2 sine x by 2.
Can we convert into form of any trigonometric formula? Yes, but how can? Just multiply and
divide by 2 cos x by 2. Then what we have? In the numerator we have 2 sine 5x by 2 cos x by 2
and in the denominator 2 sine x by 2 into cos x by 2. So for the numerator we have trigonometric
formula 2 sine alpha cos beta equal to sine alpha plus beta sine alpha minus beta and for the
denominator we have 2 sine alpha cos alpha equal to sine 2 alpha. So if you apply this formula
then we have in the numerator we have sine 5x by 2 plus x by 2 plus sine 5x by 2 minus x by 2
divided by here alpha equal to x by 2 so 2 times x by 2 equal to x so in the denominator we have
sine x then we have sine 3x plus sine 2x divided by sine x. We have trigonometric formula for
sine 2 alpha sine 3 alpha for sine 2 alpha it is 2 sine alpha cos alpha and sine 3 alpha equal to
3 sine alpha minus 4 sine 3 alpha. Now substitute that value in the integration we can see in the
numerator and denominator sine x is a common factor so if we cancel that common factor from
the numerator and denominator we have sine 3x is now 3 4 sine cube x now it's 4 sine square x
2 sine x cos x is now 2 cos x we can see that 3 can be easily integrate cos x is also easily
integrate but sine square x we cannot easily integrate. So we can use another trigonometric
formula for sine square x sine square alpha equal to 1 minus cos 2 alpha divided by 2. If we substitute
then we have 4 divided by 2 equal to 2 sine square x equal to 1 minus cos 2x then
after simplification of this term 3 minus 2 equal to 1 minus minus plus 2 cos 2x plus 2 cos x.
Now we can integrate all the term easily and we have x plus integration of cos 2x is equal to
sine 2x by 2 so 2 2 cancel we have sine 2x plus 2 times sine x and integration constant c.
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