Thermochemistry experiment || Dissolution of copper sulphate #12thchemistry #cuso4‎@a2zpractical991

Hello everyone and welcome to my channel. I'm Sachin Shukla, and you're watching all the practicals of chemistry for 11th and 12th grade. I'm going to start the first experiment of today's 12th. The one that comes on your board is practical. For thermochemistry. Thermochemistry is entirely related to our heat. And how heat is generated, how it is transferred. We are going to see that through salt. The salt I am going to use here is copper sulfate. So basically, the aim of this is to determine the enthalpy of dissolution of copper sulfate at room temperature. The copper sulfate we are going to use here is of a hydrous molecule. That means it has 5 H₂. So we are going to see that in practice here. Alright, guys, I'm going to get started on that practical. I'm going to use this polythene bottle here. And with this polythene bottle, we are going to need one more substance. Thermometer So we are going to need a thermometer. And guys, the salt I'm going to use here is copper sulfate. So we are going to take water and dissolve copper sulfate in it. We are going to dissolve copper sulfate in water. And we are going to check with a thermometer whether heat is evolved or absorbed. If heat is released, then it will be an exothermic reaction. And if heat is absorbed, then it will be an endothermic reaction. Clear. So these two things are what we are going to see here. So guys, quickly comment that if copper sulfate is a crystalline compound that contains 5 H₂O. So will heat be absorbed or evolved? So today we are going to see that through practice. So guys, I'm going to measure 25 ml of water using a measuring cylinder. So this is our 25 ml of water. And I'm going to transfer this 25 ml of water into this polythene bottle. This is our first step. Now I'm going to take the thermometer and measure the temperature of this water. So basically, the water is at room temperature. So the room temperature will be around 26 to 27 or 28. In winter, it goes up to 25. So now I'm going to hold this for a while. And we'll see that I'm going to check its temperature now. So guys, its temperature is running at 29 degrees Celsius. So this is our initial temperature. In your observation, it is written as the initial temperature. So this initial temperature is 29. Which we also refer to as T1. Now we will start our point number 2. Where should we add 0.5 gram of copper sulfate in this polythene bottle? Step number 3 is 0.5 gram of copper sulfate; we have to wait. So let's wait for 0.5 gram of copper sulfate. So guys, here we have the salt of copper sulfate. We are going to include this in our handbook, which weighs 0.5 gram. So I'm going to measure 0.5 gram. So guys, you can see here it's showing some readings. So now, when we keep this, it will show some reading. We have to tear this down. This is the tear button. When I tear this, it will become zero. Now I'm going to add 0.5 gram to this. So guys, here I've added 0.5 gram of copper sulfate. Now I'm going to dissolve this in the polythene bottle. And I will note its temperature, which will become T2. Alright, guys, here I have copper sulfate. Now I am going to transfer this copper sulfate into this polythene bottle. So you can see I'm going to transfer this copper sulfate easily into this polythene bottle. I'm going to transfer this copper sulfate easily into this polythene bottle. You have to do this very quickly because it starts dissolving. So guys, when you dissolve this, you have to close it immediately. And you have to shake this thermometer inside this. And you must enter this thermometer in here immediately. Now, guys, when you insert this thermometer into this. So it's going to display a temperature here. So now I'm going to check this temperature. Earlier it was 29, now let's see how much is coming. So now, guys, you can't see it, but let me tell you, it's gone up to 27. How much has it gone? 27. So it's showing 2 degrees less. What is it doing? It's showing a temperature 2 degrees lower. So let's go. The temperature you will observe upon dissolving copper sulfate will become T2. Clear. And what you need to do is that later you will have T1 and T2. And you have to remove delta T. So how will you calculate delta T? T2 minus T1. T2 minus T1 means the temperature of your water is T1. And the water and copper sulfate that is dissolved is T2. So if you calculate T2 minus T1, whatever value you obtain, we will examine it here. And this is very interesting. Clear. So if it comes out negative, it means heat is being absorbed. And if it comes out as positive, it means heat is being released. Guys, in this experiment, what happens is an endothermic reaction. Because you have observed that heat is being absorbed. Because earlier it was 29 degrees Celsius. And now it's reaching 27 degrees Celsius. It means that the heat from our water is absorbed by copper sulfate. Due to which T2 is coming. How much is it coming to? T2 is basically going to be 27 degrees Celsius. It means that heat is absorbed. Heat is reduced. Clear. So we will quickly perform its calculation. Which you can see in front of me. Now what can you see here? What is Q equal to? M as ΔT. Clear. So all the values are written there. You can see 25.5. So you just have to enter the value of delta T here. Clear. And when you input the value of delta T, you will obtain the value of Q. And guys, finally, what do you have to do? You have to enter the value of Q. And divide it by 2 into 10 to the power of minus 3. Your worth. Your answer. Your delta H will be in joules. Now in which one do you have to convert it? Delta H Sorry. Now into which one do you have to convert it? In kilojoules. So, to convert it into kilojoules, what do you need to do? Divide it by 10. What will you do with 10 raised to the power of 3? Divide it. And as soon as you divide it by 10 raised to the power of 3. You will receive your answer. So, guys, at last. What is written at the end? The enthalpy of dissolution of copper sulfate. Clear. So you have to show it in plus. What do you have to demonstrate? In addition. Due to the sign convention of endothermic reactions. Where is it? In addition. And in exothermic, what is there? In the red. But what is our practical demonstrating? Endothermic reaction So guys, thank you for watching this video. And please subscribe to this channel. Thank you.