use of micrometer screw gauge 11th physics practical #11thphysics @a2zpractical991 #class11th

Hello everyone, and welcome to my channel. So friends, my name is Sachin Sukla and you are watching A2J Practical. So, friends, today's experiment is from 11th physics. I'm starting experiment number 2. Experiment number 2 is the use of a micrometer screw gauge. How to conduct the experiment? I will provide you with all the solutions here. I'll tell you one more thing—I have a playlist with all the videos on chemistry and physics. Go take a look at it. You will receive all the videos with answers. So let me conduct the experiment and show you. So that you have no doubt. You don't have to go anywhere. So let me begin the experiment and show you. Experiment number 2 is the use of a micrometer screw gauge. So basically, you're looking at this diagram of a micrometer screw gauge. So I'll show you how it actually looks. So you can see that I have a micrometer screw gauge. You are able to see this. And basically, I can see a glass plate and a wire here. I basically have to determine the diameter of these two. What to find out? Diameter Now look at this screw gauge. It must look exactly like this to you. This is called a strut. This is called a screw. This is the one above. It is called a circular scale. And this is called a pitch. This is the one inside. Can you see? This is called a pitch. Pitch means this is our main scale. And many times you are asked about the pitch during the Viva. So basically the pitch here is 0 to 1, 2, 3, 5. Can you see? Thus, the difference between the two successive pitches is 0.1. What is the difference? 0.1 Clear? So now I'll move on. You are asked about the least count of this screw gauge. So I'm going to tell you how to determine the least count. But first, I'll tell you some things. Our micrometer screw gauge is of three types. One is the zero error one. So I'll tell you how the zero error one will be. Can you see? This is the main scale. Can you see? This is essentially coinciding with the zero scale. Can you see? This is the zero line. And this inner line is the main scale. So you see how this zero line coincides with the main scale. Can you see zero here? This zero coincides with this zero. It means it will align like this. So this will be our zero error. What will be zero? Can you see? It's touching zero. Let's see what the positive error is. So basically, what happens in a positive error? This circulating scale is slightly below zero. It means it will be slightly below zero. So this will be our positive error. And if this is the main scale of zero and this is the circulating scale. Thus, the circular scale will be slightly above zero. So we will call it a negative error. For example, if it is slightly above zero, then it will result in a negative error. What will happen if it is below zero? Positive error. Click. And this is negative and positive. For now, mine is zero error. Can you see? This zero is touching this zero. Now you are seeing the smallest division on the main scale. So how much is our smallest division on the main scale? It is written in one millimeter. So how can we write it more? We can write it in 0.1 centimeter. We can write 0.1 here. So you're seeing this screw. Now what is here? This is the main scale. This one inside is called the main scale. What is the difference between the two successive lines? It is 0.1. How much is it? It is 0.1. Let's quickly review our list. Let's see the number of divisions on the circular scale. So you are seeing 0, 10, 20, 30, 40, 50, 60, 70. And this is 90. And what happens after that? 100 after 90. So what is 100 in this? The number of divisions on the circular scale. Now, friends, our main important thing is the list count. Now let's get to our list count. So how will you determine the list count? Pitch according to the number of divisions. So we know how much our pitch is? It is 0.1 centimeter. And how many divisions are there in this? It is 100. So if you divide it, you will get 0.001 centimeter. This is the list count. Friends, you must remember this list count. The scale division of this micrometer screw gauge is 0.01 centimeter. Now what are we going to do with this? I will tell you in the next experiment. Friends, now you are seeing 0 errors here. So I know that its zero error is zero. 0 centimeters. Because I told you about this main scale and this circular scale. What does it do at 0? It matches. I have shown you this. What is at 0? It matches. It coincides with 0. So what will happen to us? 0 errors. What will happen? 0 errors. So let me show you the reading quickly. First I asked about the wire. And there are 3 observations. So I take a wire here. Clear. Now how do you have to figure out the reading? You have to take this wire. And you have to put it here like this. Okay. In the middle of this. You can see this ratchet. What do you have to do with the ratchet? You have to rotate it. Clear. How long do you need to rotate it? Until a sound comes out of it. Clear. See this. There is a sound. This means it is locked in place here. Now what can we do with this? We can remove it. Clear. And we can see the reading here. So our reading is basically how much is coming in here? This is 0.1. This is 0.2. Here is our 0.2. After that, I asked about the coincident division on the circular scale. Now let me show you the coincident division. How do you see? You must be seeing this. 50 This is 55. What is this 55? What is on 55? This circular scale is bringing the main scale into coincidence. What is it doing? Coincident. So, what exactly am I supposed to write here? 55 What do you have here now? Circular scale reading. So what do you have to do? B to list count. How much is our B? Here B means that the coincident division has occurred. So this is 55 into list count. How much is ours? 0.001 Now if you multiply it. So you will get. Friends, this will come 0.055. Now let's see how to get observed. So here D0 is written. So how will you obtain it? You will do A plus C. See, this is your A and this is your C. So what do you have to do? You have to add 0.2. From whom? 0.055 If you do the total plus, you will get 552.0. Means 0.255. What will you get? 0.255 Clear. Now you see it corrected. So you know that this is not my zero error. Clear. Means that the main scale and the circular scale were both aligned at 0. So there was no error. Neither negative nor positive. So the value you will get here is 0.255. You have to write the same here. If you had any error here. So where it matches, for example, it matches at 0.3, it also matches at 4. So if you have a positive error, then you will have to subtract it. And if there is a negative error, then you will have to add it. Let's see later. Let's take another reading here. Okay. I took this wire gauze. I will put it here again. Okay. And you always have to rotate it. You will rotate it. And as soon as a sound comes, you will stop it. Clear. Now stop it. Now you have to see where it's coming from. So, how much is it coming to in total? 1, 2. That means it's arriving at 0.2. So what should I write here? 0.2 Clear. And where is the coincident division? So let's see. Mine is basically coming in at 65 at this time. Where is it coming from at this time? See, this is 60, and this is 65. Can you see this long line? Now what is this 0? It's a coincidence. What is this? Coincident. So what should I write here? 65 Clear. What will you do now? Multiply the list count in 65. So you will get 0.065. Clear. Now how did you get D0? I have told you what you will do to A and B. You will add. And as soon as you add A and B, you will get 0.265. Now I have no errors. So 0.265. I'll take one more reading here. What am I supposed to do with the wire now? I take a little from another place. I keep it here. And what do you have to do? You have to keep rotating it over and over. And now it has come. Can you see? And now what do you have to do? You have to take the reading there. It's the same for you. It's only 0.2. Clear. And how much is mine? I see. This time it has reached 65. So here 65. Now what is B into list count? What is B? How many is this 65 in the list count? 0.001 So if you multiply this entire value by the list count, you will get 0.065. You will get 0.265. And there is no error. So we don't need to add or subtract. We will get the same. So now we will do this. But first, we remove the glass plate. Whose glass do we take out? So, see this—I have a glass plate from this plate. What do I have? Glass plate. So what do I have to do? I have to place this glass plate here. Clear. And after placing this glass plate here, what do I need to do? What I see is this; you have to rotate it slowly. As soon as it is fixed, you will immediately hear a sound. Alright, I'll do it and check the sound. So what should I do? What is the glass plate? Look here, you've got a fix. That means here, it's fixed. Now, in its validity, as far as I can see, 0.1 appears in its validity. Why are you giving me the ARHO? It's for the 0.1-scale reading. Pawa. Pani, jo pawa, kya aageyal ka, to rockaraar kaisi laata hai? Sarroke, Pangi was?? Those, the demand of Korese, the readiness of curd or Rukaraki, the faith of the path, the readiness of the ritual. This will be ours, 0.1 That will be 21 How will you do B x LC now? B, this is yours, and what is LC? 11 count is 21 × 0.001 You will get it if you do it. 0.021 After that What will you do to A and C? Add these, this is your A, this is your If you add it up, you'll get it. 0.121 What should you write now? Zero error from It's about subtracting, not adding. If we don't have any zero error here, then the reading here is Write it here, the same as before Now I take another reading. It's the same glass rot. I'll keep it here. And I'll fix it. And who are you supposed to turn? I'll spin you around properly Spitting out Voice Got it, this one Now that the voice has come, you need to see where it is. It's coinciding completely, exactly the same Someone is cheating at 0.1, and its What is visible at zero point one This is 0.1, the reading on the main scale here. Where is the reading of the circular scale? It's at 20, it's back at 21 Where is the reading of the circular scale? It's 21, so I'll just write it down here What will happen from the return? 0.1 It will be 21, 21 Multiply by the list count, you get 0.21 This will be given to A and C. If you add, you will get 0.121 What will happen here? This corrected value is ours Something is nothing, so write it semi to you And third, friends, do it the same way as well If you want me to write, I'll just write it here. I had just taken it out from here, so I got it, from the 20 list count Same reading, you both Plus it, and you'll get 0.121. And this corrected value You'll get the same thing too; now let's go. We will calculate the mean towards the mean of both. Clear, so friends, right now we Let's go toward the mean, then the mean will have you How to extract, look, 123 value 0.255 plus 0.265 You need to install the app. From three, now when everyone has this I will add it; you will receive all three. 0.785, divide this by 3 You will get 0.261 I mean, the value we have here 0.261 0.121 0.125 divided by 3 If you add all of this together, you'll get it. 0.367, and when you do this to it Divide by 3, you'll get it 0.122 How much will this cost? 0.122 Let's see, calculation mean diameter of the wire So this is basically your diameter. 0.261, the mean that came out of yours So 261 radius of the wire, divide d by 2 I mean, you have to divide this by 2, the one that's this way. So when you divide this by 2, you'll get It will be 0.1305 the area of cross-section 3.14 0.135 0.1305, this is the whole You will get it if you multiply. 0.0551, this is for you It will be found here now If the thickness of the glass plate is asked, this is it. Your, 0.122 centimeter, also in the result You should write the same thing; you can take the diameter from here. The area of the cross-section has been provided to you. 0.0551 thickness of the glass meter You can write it here A precaution for you Let me inform you that you What is a ratchet, you need to Don't press too hard, or it'll all fall apart. It's a gauge; what will happen to the whole thing, it'll be ruined. It will become Your screw gauge is complete. It will go bad, and this will indicate your error It will feel as if I've been here I informed you about the error, it's clear, and Do not apply pressure to this screw gauge. There's no more pressure on you, let alone on top of this. You need to apply, the other thing is you Never turn this, you should never always turn this Pressure remains, then Pressure keeps building, okay So you have seen how the micrometer screw is used I have given you the complete solution. Yes, and it's a very easy experiment.