To determine internal resistance of the cell || using potentiometer #12thphysics @a2zpractical991

Hello guys and welcome to my channel Friends, my name is Sachin Shukla and you are watching A2J Practical. Friends, today's experiment is a 12-physics experiment. So basically, the experiment I'm going to start today is Experiment No. 11 to find the internal resistance of the cell And this is a very easy experiment. Friends, let me tell you one thing All experiments related to 11, 12, physics, chemistry Go take a look at it. If you like it, then share it with your friends. Friends, support me a lot Because one subscriber means a lot to me So let me start the experiment So, friends, this is your diagram We need to determine the internal resistance of this cell. And this is your diagram You must set up the circuit according to this diagram. So let's quickly see This is our A terminal and this is our B terminal. So you see here This is your A terminal and this is your B terminal This is a potentiometer wire. It is 4 meters long. That is 100, 200, 300, and 400. This is how it is divided This is a scale You can see the scale here By measuring this scale, I will tell you everything. This is a Lanklench's cell Lanklench's cell is basically made of This is a carbon rod and this is a zinc rod. The carbon rod is positive here. And the zinc rod acts as the negative electrode. And there are some solutions here These are the solutions of ammonium chloride. This is a galvanometer. This is a resistance box. This is a voltmeter. These two keys are going to be used. And this is our true story Okay Now let me show you the connection quickly. First of all, you have to provide three connections from A. You have to give one to the battery. You have to give one to the Lanklench's cell. And you have to give one to the resistance box. This is your A terminal What will happen to Terminal A now? There will be three connections here. What is connected to the A terminal? One is positively connected to your Lanklench's cell. Now look at this, this is Lanklench's cell. This is positive and this is negative Lanklench's cell's positive terminal is basically connected to A. The second connection here is the positive terminal of the battery. Look at this The positive terminal of the battery is also connected to A. And the thread of the real story is also connected to A. Let me quickly connect. This is my Lanklench's cell This will also be connected to A. Battery Look at this; this is the positive terminal of the battery. This will also be connected to A. And this is our resistance box, positive for Lactate dehydrogenase. And the positive terminal of our battery—how are these three connected? We're connected to A, right? I will connect all three wires here from A. OK? What are you supposed to do here? Lacklance's positive, battery's positive And one wire from the resistance box was said to be thin. They will all be at Armil, we are already connected at Armil. Okay? Fronts are the ones that will be connected to our key in the second end. And whose second end will connect to whom? Do you see the galvanometer? The second end of the resistance box that is connected to Kadalani Trana Nandte Cadet Kupwate Cadetanké Cadeteku Cadet Tent Look at this, or give the Chandrakala Sil Dohar to the temple. It's about connecting the galvanometer with 2 wires. This path is the negative charge of my LXM-7. My little sister's silken scarf, the one with the blue pattern, is gone. The zinc rod that is connected to it will become mine. So you are in the galvanometer Lagbaba 2 Bayar Connect Muraya yeda raha jemachatе And the second one, which is the mango Who will it connect to? Rear Stud Lusara Need So you are looking right here The battery's negative connector remains connected. The other one that is It will connect to a common one of the rear studs. How do you recognize them? I called the ponds with 'b' variables. I'll connect you to the B-side pond Pay Friends, I'm sorry, but I can't assist with that request. It will be displayed on the terminal. There is a terminal at the Aftabnagar side. The positive terminal of the battery is one. But calling the positive terminal of the battery a "positive terminal" is your one and only option. Outer side of the prestressed box terminal The world says you have gone You are the one who is nice. One. After that The negative terminal of the cell Disconnected In Ji It is connected to the terminal. Two, in the middle of the mango And the variables that are That's a very good question. variables are That's spectacular Here. After that The negative of Laglanc seal The one like this Zinkerröt Zinkerraut is connected to whom? Galyalon Vider. Now I'll check the Pada Pada. If both sides show deflection So, whatever you have here will be correct, okay? Here, both side deflections should be visible here. So, Dikie Show, I'm deeply touched by this kind of affection. A side deflection has been shown. I'm coming near the vaccine site. And as I touch the second terminal It will show second-side deflection. It's fine here. Now I'll quickly show you the reading I've taken. So, fronts, I'm fat-fat balancing length I'll figure it out; I need Jocky for this You have to glue the potentiometer wire over the potentiometer. As it will show zero deflection in the galvanometer I'll infect Jacky with the disease on the same wire. And as much as the sentiment remains What should I do with him? I'll note it down. You are seeing, little by little, in this It stays in the second one. Kate, what else can he do, he'll have to close it. Then I'll take your five. And I'm closing this, okay And I will find out its reading. How much is coming in, then what am I supposed to do with it? I will start moving from here I'm going to move, and I'm showing up. Here in the calorimeter It appears to be approaching zero, as if it's at zero It will come, whatever this length of yours is, this one Note it down; how much length am I getting? Now you have to do it for 10 So I took out 10 from there I'll move it back myself, and do something like this Time will come when it will reach zero. And as it reaches zero And you have this length I'll show you the filal right here. The length here is 55. Okay, so how long is my length? Will come, 55, after that I have to do it for 15, okay So I've removed 15 from here. And what should I do with Jokey from here on? But there will come a time when this They started at 0, and will proceed just like 0. And what should you do with this reading, take notes? So, this is Filal 73.5 And how did it get here, at 0? It's done, okay, it has come to 0 here. And this is my galvanometer, where did I put it? I'll find out the one from the past for 20. I'll find it out for 20, same You are to galvanometer this It must be taken from above the Vārī, and something like that The time will come when the galvanometer will reach there. 0, okay, as such It will go to 0, the reading will be yours. What to do, here I need to note it down, so this is mine 84.5, correct Alright, let me tell you the calculation. So friends, right now you What can I do, I've already experimented. internal resistance of the cell I found out, so I put it in the resistance box. Who had taken which resistances before? 5, 10, 15 20, correct, for 5 The balancing length I obtained for L2 was 13.5, correct 55 for someone else, 73.5 for someone else And for the fourth How much was my income for the fourth? 84.5 Alright, so friends, your balancing length K2, that is How much did I get for L1? 102 Okay, 102 cm was obtained. Okay, balancing length Now I'll give you the calculation, this one's quick I'll show you the internal resistance How will we find out? The formula for internal resistance is given. r is equal to l1 minus l2 divided by l2 into rb What is your l1? l1 Your 102 What is l2 13.5 divided by l2 Divide by 13.5 And what about you, RB? 5 If you calculate this Then you will get it. 32.7 Now, do this Do it for all of you Internal resistance L1-L2 divided by l2 into rb So what do you have to do, you know What is l1 102 What is L2? 55 divided by into rb What is 10? And what is L2? Do you know how much l2 is yours? 55 Then you will get it, 8.54 This one is yours It's also taking you to 5.8 for R3. Alright and Last, how much am I getting? 4.14 Alright Then I also provide all the values. How much I got for 1 32.7 For someone else How much did I get? 8.54 For the third one How much am I getting? 5.8 How much am I getting for the fourth? 4.14 Next, what do you need to do? Three to the heel, four to the heel If I divide by four, I'll quickly get it done. 32.7 liters 80.54 Lass 5.8 liters 4.1 Here comes 51, so I'm gonna take it I have to divide by 4. How much has come in, fronts here? 12.8 Alright So, Fronts, have you seen the experiment? This experiment. A lot of effort is required to create it. So please support me and this channel Subscribe and stay updated So that I can get motivated for you For making a lot of videos