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hey guys and welcome back to yet another
one of these maths Made Easy videos
today we're going to be looking at
binomial expansion and in Brackets it
says positive integer Powers because in
A2 we get to learn about fractional
powers and negative powers and all that
fun stuff that we love so first things
first what is binomial expansion let's
quickly discuss all the different ways
that I'm going to help you in your GCC
or A- level maths careers first of all I
wanted to talk to you about the YouTube
members this is a really cost effective
way of getting tutoring so I'm going to
do we live streams for GCSE and AEV
maths and that all comes for £18 a month
and you get at minimum an hour of
tutoring per week in these live streams
at the moment they're quite small so you
basically get tuition for about £450 an
hour which is really really cheap the
second thing is the patreon for those of
you doing a level maths I have already
completed as stats on my patreon is a
full class with worksheets mark schemes
videos I answer all the questions we're
going to do exam papers and everything
that needs doing we're halfway through
mechanics as of yet and lastly there's
tuition I still have places in my group
classes for a level maths and GCSE Maths
for GCS it's £3 an hour and for a level
is £40 per hour so if you want to let me
know if you're interested just email me
or join the Discord where I'm very very
active all the time anyways back to the
video why do I care well let me take you
through a little story so to speak so if
I asked you to
expand this bracket right here you would
say that's nice and easy it's x + 1 then
if I asked you to expand something like
x + 1 2 I'm hoping that you'd be able to
get to x^2 + 2x + 1 because what you'd
have is you'd have two separate brackets
that you can then expand and nice and
quickly get to the final solution and
then if I ask you to do x + 1
cubed well then you probably have to
expand it like this x +1 x + 1 x + 1 and
then you pick two brackets and you do
this thing where you expand the first
two brackets which be X2 + 2x + 1 and
then you'd still have the x + 1 so now
you have to expand the bracket again so
then you'd have X2 X cubed sorry plus
X2 + 2
x^2 uh + 2 x + x + 1 and then you would
close that all up nice and neatly to get
X Cub + 3x 2 + 3x + 1 right well okay
and then what if I asked you to expand x
+ 1 to the power of four well then you
probably tell me to uh you know well I
mean I'm not going to I'm not going to
say what I was about to say you probably
tell me to go and do something right
because it just gets unreasonably
difficult and in fact it gets
exponentially difficult because you have
to expand more and more and more and
more terms now funny enough there's
actually a pattern between expanding
with one the power of one power of two
and power of three now what would make
this really easy if you have a look if
you notice the power of X just goes down
right so it goes from X to the 1 x to
the 0o we have x to the 2 x the 1 x 0 x
3 x the 2 x the 1 x
0 so if we could somehow work out what
the coefficients were we could expand
even x^ 4 really really easily because
all it would be is x
4 plus something X cubed plus something
X2 plus something X plus a constant
1 now if I just work out what the
numbers in front are I would have
expanded the bracket in a much quicker
way now there is a way to do this
actually the first way is called
Pascal's triangle and it is the same
Pascal
who has a unit of pressure named after
him so Pascal's triangle and this is how
it works so we start off with just
one like this this is for nals 1 in fact
I'm going to move this slightly further
away so this is going to work for x + 1
to the^ of n it's going to give me the
coefficient so if you notice that Nal 1
we get one and one and if you look the
coefficients of both of these is one
then you keep kind of spreading
out this and the middle is going to be
these two added together which gives me
1 2 1 and if you have a look at the
coefficients for any equals 2 you get 1
2
1 cool right so one that's going to be
three now cuz we add one and two uh
that's going to be three and that's
going to be one and if we have a look at
the coefficients of X cubed we have 1 3
3 1 okay so now to do xal sorry Nal
4 all we have to do is spread out the
one again and we get 4 6 4 1 so then if
I go over here my answer will be well
there's a one in front of the X to the
four so don't write anything uh then we
have 4 6 4 1 how cool is that expanded a
bracket really really quickly okay but
then what if I had something like x + 1
to the^ of
10 could you see writing out all these
numbers all the way to Nal 10 is going
to make me want to die it's too tricky
or at least it's too long right it's not
tricky adding numbers is nice and easy
for us but it's going to take us a
really long time so is there yet another
way the answer is yes if you pull out
your
calculator Tada I want to expand this a
little bit just to make it a bit easier
for you to see you have a very special
button called the NCR button hopefully
you can see that so it literally has the
letters N C and R there and we get there
by pressing the shift key and the Divide
symbol now if you have a different
calculator then of course it's going to
be different I know shocking so I'm
going to just quickly look at write down
NCR n is simply the power of the
bracket and R is I like to call it it's
the position that you're in now if any
of you do programming or know anything
about programming Position will make a
bit more sense it's like an array a
string and we start counting from zero I
know weird but you will get used to it
extremely quickly which is good so for
example if I want to generate the first
coefficient in an Nal 4 expansion I
would simply put four here and i' put
zero on the end and it would give me
one if I change that to a one now I get
four if I change that to a two for the
Third third value I get six so can you
see I'm generating them all on a
calculator nice and easy perfect this is
what we're going to use to expand
brackets of any size really bloody
useful now let me show you how to do
this with a question now of course we
don't always just have x + one we may
have 2 plus X over 2^ 2 or 2 x over2
sorry something along those lines so let
me show you how this works
first thing it says is it find the first
three terms in ascending powers of X
okay so what I want you to do now first
thing first is we're just going to write
the coefficients down so what is our
power our power is six so I'm going to
change the four to a six and we're
looking at the first coefficient zero
and if you notice from Pascal's triangle
it's always going to be one and the last
one's also going to be one but you know
in for a penny in for a pound might as
well do it one then I'm going to leave a
bunch of space and I'm going to put the
next coefficient
one gives me six cool plus six big space
you don't need to leave that much space
but I like to and if you notice it says
the first three terms so that's the good
thing about this is we don't have to
generate all of them it will normally be
the first three terms sometimes four but
usually it's three terms in exam
questions nice and easy and then two we
can just do that and then boom we get 15
that's the first step
now this is the really important part
ascending powers of X so you know how I
said usually it's the first three terms
in I mean almost always it's the first
three terms it's also always ascending
powers of X which is the which is really
really really nice so what that means is
you're starting actually from you're
going backwards now that might sound
more tricky but it's not because I'm
going to show you what happens do you
remember how I said the power of the X
term goes down right so it goes from x^2
x and then x 0 here it goes x 4 x Cub X2
X1 x0 okay so if you're going in
ascending Powers we're going backwards
it be x to the 0 first okay so this x
term which is X
over2 goes like that now something that
we didn't spot because we had x + one is
that this plus one term actually
increases in power as we go along so
in this case we start off with the
highest value of x and we start off with
the lowest value of the constant
term and then as we reduce the power by
one we increase the power of the
constant by one so since we're going
backwards as I said we're going to be
over time increasing the constant um
sorry increasing the power of the X term
decrease the power of the constant so
what's the biggest power of the constant
it in this case it's 2^
6
now that might seem a bit confusing but
Watch What Happens we reduce the power
by one and increase this power by
one reduce this power by one increase
this power by
one because that's how it works when you
expand brackets however when we expand
brackets we normally decrease the power
of X by one increase the power of this
by one however with binomial expansion
because we're going into ascending
powers of X we're going to increase the
power we're going to it backwards
increase the power of X over time
decrease the power of the number the
constant over time that's it four marks
all we have to do now is simplify it so
so easy X over 2 to^ 0 is going to be
one so literally all we're doing is
doing 1 * 2^ 6 so we have 64 as the
first
term now what we do for the next one
well all we have to do is change the
coefficient change this power to five
now of of course we actually still have
1/ two right don't write X on the
calculator because it won't know what
you're talking
about so it's
96x and again what we're doing is we're
changing the constant the front reducing
the Power of Two by one increasing the
power of the half by
one and then that's going to be 60
x^2 that is four marks
four marks two lines of working out they
did it all on a
calculator so what are the problems why
is it worth four marks well a people
tend to
forget uh to reduce or increase the
power in fact a lot of students actually
skip this first bit here they ignore it
so then they don't put the one which
means that they can screw up the later
Parts other reasons is because people
don't take it slowly they've given you
four marks it's a roughly 4 minutes
use that time take it slowly work
through it you have a lot of
time so it then says use your expansion
to find an estimate for the value of
2.05 to^ 6 so how do we do that well
it's quite simple this binomial
expansion that we've got
here looks like
this and it's an approximation so the
wiggly equal signs means that it's a
oximation it's it's shaky you know it's
roughly like this and we want to find an
approximation for 2.05 power 6 if you
notice the power is the same right so in
other words what's inside this
bracket should equal 2.05 so the first
thing I do is I minus two from both
sides we get X over 2 =
0.05 times both sides by two we get x
equal to 0.1 so in other words all they
want me to do is substitute in
0.1 in for X but you need to show that
you've worked out X okay so that will
give me
2.05 to^ 6 being approximately 64 +
96
0.1 +
60 and by the way this is actually what
binomial expansion is used for in real
life is approximations because certain
calculations are too long for computers
to do so we approximate
instead because if you look or if you
notice if you're a bit math
Savvy the actual value of each term is
decreasing right because here it's 0.1
so we're dividing that by 10 then we're
dividing this by 100 so the numbers are
going to get smaller and smaller and
smaller and we get
74.2 so what I like to do sometimes to
have fun cuz I'm a loser is I like to
just do 2.05 power six and see what
happens not bad 7 4.22 not bad at all
hopefully that makes a lick of sense and
we'll move on to the next one now of
course there are always different types
of questions that we're going to do so
I'm going to give you an overview of
every question that we can do part a
very similar so what I would like you to
do right now is pause the video and have
a go yourself at doing this again uh
with maths is a very active subject you
need to practice yourself so I'm going
to assume that you've done that you
better have but all we're going to be
doing is once again using the NCR button
on our calculator to work out the
coefficients first so whip out the
calculator we want shift NCR button what
is the power the power is seven start
off with zero and we know it's going to
be
one so one leave a gap plus and what
does it say the first three terms again
so we're only going to go up to two
seven and
plus
21 like so now what do we do we start
off with the highest power of the
constant and the lowest power of the X
so we have 2^
7 and then we have Min - x over 8 so it
is a negative so we need to make sure we
keep that negative
and then we keep going so reduce the
power of the constant by one increase
the power of X by
one very
formulaic very formulaic but you may
have made a couple mistakes in you're
working that is completely fine it
happens as you uh practice you will make
fewer and fewer mistakes I guarantee you
so let's work it out well of course the
first one is just going to be two 7even
technically it's Times by one but you
know
it's not that is it so
128 then um I'm not going to put as plus
cuz I can see it's probably going to be
a minus so we have seven Open Bracket 2
p
6 and then we have minus 1 over8 again
we don't bother writing the X we have -
56x and then the next one should be a
positive again if you're not sure you
can always up
first and so let's change that to a
squared let's change the six to a five
and let's change the seven to a
21 and we get 10.5
x^2 like so again four bloody marks it's
all on a
calculator but part B looks a bit
scarier and honestly it sounds a bit
scary
so we have FX is equal to this this
where A and B are constants given that
the first two terms in ascending power
of X are this and this find A and B so
what they're trying to tell me
is if we were to expand This truly
gargantuan bracket here we will get two
terms the first two terms in ascending
power of X is 384 and4 x well we've
already kind of got the first two terms
all we need to do is times it by a X
plus b so this is not an approximation
in this case because we're only looking
at the first terms in ascending powers
of X
anyway so now I'm going to use my now we
have to expand this now if you use your
nogin a little bit you realize you don't
have to actually expand that much so why
is that well we're looking at the first
two terms in ascending power of X in
other words we're looking for the X to
the zero term and the X terms so when I
multiply out this bracket anything that
gives me x^2 or X cubed I can ignore so
let's have a look at
this ax * 128 is completely legit so
128 ax but I can't do ax * 56x cuz that
give me x s and I can't do ax * 10.5 X2
because going to be X cubed it's too big
I'm only looking at the first two terms
so let's go to B well 28 * B that's
completely legit
too and B * 5656
BX is also correct so now let's put this
in like order ascending powers of X
because again it tells me in ascending
powers of X so we start with the
128 B then we have
128 ax minus 56 BX so these are my first
two terms we have 28b is my first term
and all of this is my second term and it
tells me what they're equal to so 128b
the first term should be equal to
384 divide both sides by 128 and I'm
going to pray that this isn't an ugly
number 128 actually I think it goes in
yeah three times perfect so now I know
that b is three and it tells me that the
X term the second term should equal -4x
so in other words we have
128 ax - 56 BX but B is three don't
forget
equals
-4x so what's my first move here well
the first thing I'm going to do is I'm
going to divide
everything by X so in other words I'm
going
to delete all of the X
is that will give me 128
a - 56 * 3 let's work that out so 56 * 3
gives me
168 equal
104 add 168 to both
sides gives me
64 so then a is equal to 64 / 128 which
is a half
so a is a
half and B is equal to
three not that bad
really it looks like it would be bad but
it's not that bad by the way this is
practically guaranteed to come up in
your year 12
marks so just keep that in mind eight
marks
huge huge about what 10% of Pap of of
the paper you're do in year
12 so overall 5% of your grade just on
this not bad increase your grade by 5%
that's not bad at all that's quite close
to a grade
boundary here we
go now here's where things get
interesting so with um a level maths
they really really like to do something
called
symbiotic maths so that sounds really
fancy and it's not about like Venom or
anything what it is is it's using
different uh parts of maths in other
parts of maths so this right here is
actually a Statistics question I know
right so they've taken statistics put it
in pure maths with regards to this so um
this bit here
is fully expand I know it kind of sucks
right it kind of
sucks but since we're fully expanding it
doesn't matter to the order but the
first thing we need to do is once again
get our good good old fashion NCR button
and work out all of the coefficients
this will not take too long I promise
the power is five we're going to start
with zero and we're going to end with
five right so we have one and then
plus
uh five
yeah so this it doesn't actually take
that long because there's only going to
be five terms well six terms in
total
[Music]
10 uh and again since we don't actually
have any numbers it's literally just
going to be like P to the 5 P4 q1 P3 Q2
like it's not actually that bad um when
you get used to it uh five and then I
know that the next one's going to be one
and if you notice it is symmetrical when
you have an odd
number it can't be symmetrical when you
have an even number of course but when
you have an odd number it's always um
symmetrical which is nice and then again
like I just said it doesn't matter if
you start with P or Q to be honest
because it's fully expanding but it's
going to be P to 5 q 0 P to 4
q1 p 3
q^2 p to 2 Q cubed Q cubed interesting P
Q4 and then Q to the 4 so if we simplify
this we literally just have P 5 + 5 p
4 q+ 10 P cubed q^2 God I hate saying
that 10 p^2 Q cubed + 5 P
Q4 Plus Q to the 5 I forgot to actually
increase the power thank God I spotted
that there we are
oh there we are not too bad um slightly
more annoying but we should keep in mind
that it is
technically easier to an extent but now
here's where things get spicy so we've
got four Mark we've already got most of
the marks in the question and we haven't
even done the hard bit what in well in
my opinion the hard
bit it then
says uh let the probability of Dave
being late on any school day 0.1 so0 so
p is equal to 0.1
right so then Q would have to equal
0.9 and it said it I mean it tells you
use the last two terms of the expansion
so these two yeah find the probability
that Dave is late no more than one time
in a school week well if you
notice the probability of him being late
once is going to be he's late once and
then he's on time on time on time on
time so if you notice that actually
gives us the
answer and the other probability the
other outcome is that he's never late so
he's either never late or he's late once
we're not including he's late twice
three times or four times because it
says no more than one time so it's just
these two terms here and all we need to
do is literally sub in the probabilities
that they've given
us and that's three marks by the
way three marks for doing a simple
substitution on your
calculator but again it's the
conceptual knowledge knowing to do that
which is a I mean it's obviously very
tricky and it's brand new as well right
like you're not really expected to do
stuff like this in GCSE so the fact that
we have to do it now is scary but it's
not that bad and I'm going to get you
through it okay just practice learn and
if you are ever unsure about what I'm
doing or why I'm doing something then
let me know leave me a comment and I can
help you out I can explain it again so
that right there was the binomial
expansion in that shell so I've gone
through a few different exam questions
uh that can turn up in your year 12
papers so all you need to do now is go
and practice it it's very similar every
single time it's not that bad and I know
that you're going to get it but anyways
I'm going to leave you to have a
wonderful day and I'll see you in the
next
one