Hoá 11 || Sách mới || Chuyên đề 3: Sự điện li, Phân loại chất điện li, Thuyết Bronsted Lowry

Hello everyone, in today's video, I will continue to guide you through the 11th grade science program, the new book, and today is the 3rd subject. Electrolysis, Electrolysis of Acetate, Acetate theory according to Rontek-Lowry. I do it according to the subject, so it should be used for all three books. The book of many wings, the book of knowledge and the book of creativity can be used. And this subject is the 3rd subject of the 1st grade. Currently, we have a total of 7 subjects in the 1st grade of science. Use for all 7 subjects in the book. And this subject is the 3rd subject. This is the document that the teacher printed out for us. If you want to receive a document or join this help group, If you want to receive a document, we will join the help group. The teacher called this group to help study. When we join the group, we receive documents for a year and are specially sponsored for study. Currently, in the group, there is a document of the 1st grade. This document is printed out from this file. This is the file that was printed out earlier. Here, there are a total of 7 subjects. The image is clear for us. This file is the subject file. 64 pages. We just print it out. If you are smart, you can do it directly here. This is the subject file for us. And this is the text file. 166 pages. Each topic has a guide for us. If you want to receive a document, we will join this help group. The content of today's video will guide us. The first is the concept of magnetic field. The second is the magnetic charge. The third is the non-magnetic charge. The magnetic charge is strong and the magnetic charge is weak. In this section, we will learn more about magnetic conservation theory. In this section, the teacher will give us instructions on magnetic conservation. Today's video may be a bit long. The second part is the exercise. This exercise is for strengthening this. When we finish watching the theory, we look at the exercise. In this exercise, there are the theory exercise and the experiment exercise. We try to watch all of this. Usually, the exercise is to strengthen the content of our theory. Now we start. Here we have a piece of paper. I'm going to show you how to do this. The third challenge. I'm going to show you how to do this. The third challenge. First, the electricity. The electricity and the non-electricity. This is the problem. So, what is electricity? Here, we can see some pictures. Electricity is the process of separating the substances in the water to produce oxygen. Electricity is the process of separating the substances in the water to produce oxygen. So, electricity, people do experiments like this to let us know if it produces electricity. So, here, let's take a close look. The electricity is different from the dissolution. For example, we put a substance in the water and we see that it dissolves or not. That is the process of dissolution. As for whether it produces electricity or not, we have to check it. If it produces electricity, if it produces electricity, then it is electricity. If it does not produce electricity, then it is not electricity. That is the normal process of dissolution. So, we have to produce oxygen. Electricity produces oxygen. So, how do we know how to produce oxygen? People use this experiment. Here, we have carbon, sodium chloride, salt, water, sugar, salt. This is the source and the light bulb. So, in this experiment, if there is oxygen, it indicates electricity. If there is electricity, then the light bulb is on. This is the experiment to determine whether there is oxygen or not. If there is oxygen, then it is electricity. And the substance that has oxygen, we call it the substance of electricity. It is as simple as that. When we put it in the water, the substance that dissolves in the water produces oxygen. This is the substance of electricity. The substance that dissolves in the water produces oxygen. And most of them, this is an experiment, most of the acids, salt, salt. Here, we take the dissolved salt. Don't call it the substance of electricity. The place where the salt dissolves, some books only write salt, some books write most of the salts. We take the substance of acid, sodium chloride, salt. These substances have electricity. The light bulb is on. Acid, sodium chloride. In addition to acid, sodium chloride, in addition to acid, sodium chloride, it is not the substance of electricity. This is the substance of electricity. It is the substance that dissolves in the water without releasing oxygen and its substance does not conduct electricity. For example, sugar. For example, alcohol, glycerol. Among the three substances of this experiment, acid has oxygen and conducts electricity. This is the substance of electricity. Succulent is sugar. Our sugar is daily. It has no oxygen and does not conduct electricity. This is the substance of electricity. And the third is salt. This is the substance of electricity. We hold it. Acid and salt are the substances of electricity. If it can conduct electricity, people will perform it by a process. It is called the process of electricity. The process of electricity is very simple. That is, it separates out which one we write. Separate out which one we write. NaCl. In the epidemic, there will be two. That is Na plus and Cl minus. That's it. HCl separates out. H plus and Cl minus. The process of separating the substances in water has the role of water. It has the role of water. The role of water is very important here. How does water play a role? Water plays an important role in the conduction of substances. This is explained by water. It has two heads. The head of the sun and the head of the moon. The head of the sun is the head of Hiro. The head of the moon is the head of Hoshi. So when a substance is dissolved, electricity enters the water, it interacts with the substances. To put it simply, the head of the water absorbs the substance. The head of the moon absorbs the substance. To make it easier to understand, I have this picture. I will give you a file. The file has a color picture to make it easier to see. This is a black and white picture. It's hard to see. Here, you can see the color. The water has two heads. The head of the sun and the head of the moon. This is Niacin. The head of the sun is Niacin. The head of the moon is Niacin. This is green. The body of the green is the head of the moon. It's the small black head that's being sucked in by the oxygen. The large head is being sucked in by the oxygen. In the end, it separates these guys out of the salmon body. It pulls them out. That's the role of the water. If there was no water, it wouldn't have been able to pull them out. This is called the hiragawa process. Hiragawa is the water. The water surrounds and pulls these guys out. That's the role of the water. Now let's talk about the strong and the weak electrons. The strong and the weak electrons. The strong electrons are the molecules that dissolve in water. The molecules that dissolve in water are the molecules that dissolve in water. Through experiments, they found that the strong acids and the weak acids were all dissolved in water. The strong acids and the weak acids were all dissolved in water. That's why it's called the strong electrons. When writing the Hiragawa process, they used the 1-digit name. 1-digit name means complete separation. Complete separation of the molecules. As for the weak electrons, when this substance dissolves in water, only a few molecules dissolve in water. The rest still exist in the molecules. They include the weak acids and water. This is the weak electron. The difference between the strong and the weak electrons is here. For example, we have NaOH, 0.1m. It will separate to form 0.1m¹ and 0.1m¹. See? The weak electron is here. We have CH3CH. We have 0.1m. It will definitely separate to form less than 0.1m¹. CH3CH will definitely separate to form less than 0.1m¹H+. Because it's ionic. It doesn't completely separate. Let's take another look. The higher the number of ions, the higher the charge. The lower the number of ions, the lower the charge. The more, the higher. Between NaOH and CH3CH, NaOH will have more ions because it completely separates. The higher the charge, the more ions. The higher the charge, the lower the charge. While CH3CH will have less charge. It's represented by the 2-digit symbol. We learn about the 2-digit symbol. In the first part, we learn about the concept of ionization. The ionization of the strong, weak, and non-ionized atoms. In this part, when it ionizes the ions, the ions in the medium, will be composed of the ions, Cations and Anions. Here, we have to understand the conservation of electrons. In a little while, I will teach you about conservation of electrons. The important points are the total number of electrons in the medium and the total number of electrons in the ion. The total number of electrons in the medium and the total number of ions in the ion. In the next part, we will understand the conservation of electrons. The second point is the theory of Rontech-Lowry and Aschersberg. These are the two Rontech-Lowry scientists. They proposed the theory of Aschersberg. In 1923, Rontech-Lowry proposed the theory of Aschersberg. Aschersberg is a substance that can give and receive H+. Aschersberg is a substance that can receive H+. Aschersberg can give and receive H+. Aschersberg can fly and receive H+. In the old days, we didn't study the theory of Rontech-Lowry. We studied the theory of Arrhenius. Arrhenius stopped at the traditional Aschersberg. According to Rontech-Lowry, he expanded the concept of Aschersberg a lot. In addition to the traditional Aschersberg, Even cations and anions can be shown as Aschersberg. But it can only give H+. This is the most important part Asics, according to Rotec Lawry, include the traditional Asics, HCL, H4, H3, H0, H0, H0 The cations of the weak flight The weak flight, except except which ratio is less than 3 Except which ratio is less than 3 There They are all Asics The cations of the weak flight, except which ratio is less than 3 Just like C6, HX and SO And also H4 The anions are composed of H, S and O This is an important part of the Asics This is important, we will list them in a moment Asics, Theoron, Tachylorem And Bayes, are our traditional 3-dimensional particles NaOH, KaOH, PaOH, CaOH, CaOH The particles with OH are Bayes In addition, there is also anion There is no cation, anion Anion of weak asics For example, H2CO3, H2O3, H2S H34 These are weak asics Their anion, their anion, their asics are Bayes And here is our definition Let's calculate Calculate Both H and H plus According to Tachylorem Calculate here can be O6 or H6 Calculate O6 or H6 There is a memorable sentence It includes chromium chromate Chromium chromate That sentence we can write It includes chromium chromate It includes O6 and H6 Chromium chromate In addition Particles with weak asics but still H For example, HO3, HCO3, HH, H2 These are still H In addition, there is another form Neutral Neutral, like A plus, C is negative That is neutral According to Tachylorem We can get the concept of asics And Bayes According to H plus In addition to the traditional Bayes asics There are also cation and anion We hold it Cation can also be asics Anion can also be asics There In the next part I will write to prove Why it is asics, why it is Bayes And the ion distribution in the water The ion distribution in the water Based on the ion distribution in the water We will be able to prove Maybe that's why it's asics Maybe that's why it's Bayes Based on this distribution According to Tachylorem Many ions For example, Fe3 plus Fe3 plus will act as acid And Bayes in the water Because they have the same effect as water Based on this process We will see if it gives or receives H plus See If it receives H plus It is Bayes And if it gives H plus It is asics Giving H plus is asics Then For example, based on this process We see It gives H plus This guy is asics This guy is Bayes This guy is asics The rest is random Now to understand this article Let's go to the article The article The theory is mainly for us To understand the theory The article has many articles This video is difficult Let's watch it for a while Article 1 For many ions Require to determine Strong ion, weak ion And non-ion Strong ion, weak ion And non-ion Strong ion Includes asics Asics And salt Salt Strong ion Weak ion Includes weak asics And weak bases And non-ion Includes sugar Includes glycerol Includes alcohol Article 1 There are 3 types First type Strong ion Second type Weak ion We will write the ion later Weak ion Non-ion Weak ion Now there are 3 types We put it in In the box NaCl is salt Salt NaCl HF HF is weak acid HF SiO4 Salt SiO4 NaOH Strong ion NaOH We will write the ion later MgO3 Salt MgO3 H3PO4 NH4 H2CO3 Weak CH3SOH Weak acid CH3 COOH AgNO3 Luco Sugar Non-ion Luco Lyserol MgOH2 Weak MgOH2 FeOH2 AgNO3 Weak HClO Weak H2S Weak H2CO3 Weak Strong ion Na CH CO HO Na OH Mg 2NO3 Remember when we write the ion We write the ion H4 B4 3- 3-4- 2 1 3 1 Ag 3- H 3- ag 3- 5 Take the first H, move to the next step H2B4- Move on to two lines Take the next H, take the next H and HB4- Move on to the next step HBO4- We take out 1H+, 1H+, and B4, 3 bars. There. Got it? Then, corresponding to H2CO3, we catch it first. Got it? This 2-digit code is weak. Take out 1H+, and the rest is HCO3. Just take out a plus and a bar appears. Continue to phase 2. HCO3. From phase 2 onwards, it's always 1-2-digit. Got it? Take out 1H+, and C3, 2 bars. There. For acids with 2H and 3H, there are many phases. There are many phases. For example, 2H has 2 phases, 3H has 3 phases. Obviously, the current is weak. But there will be some special cases. We will catch it slowly. Although there are 2H and 3H, but for example, there are 3H. This guy has 3H, this guy has 3 phases. But some guys still have 3H, but there are 2 phases. There. At the end of the phase, some guys can't catch it. So we have to know the correspondence. Give me the remaining number of acids. It's easy. Continue to phase 2. Calculate. Phase 2. Calculate. Phase 2. Calculate the male team. This one is relatively easy. I do it all. It's up to phase F. Each phase is different. Let me analyze it for you. Phase A, B, C is the male team of each acid. It's too easy. Each acid corresponds to the male team. Phase D is also an acid. But the formula is a bit difficult. Phase E is the male team. The male team is the same. We sum it up. Phase F. The male team has a reaction. Phase E is the male team that has no reaction. So there are 4 sentences above. 4 sentences are the male team of each acid. Each acid separately. Phase E is the male team that has no reaction. Phase F is the male team that has a reaction. Let's do the previous part. This is the formula for the male team. After this topic, there will be a separate exercise topic. Let's simplify the previous part. There are 2 males here. H and XO4-. H. There are 2 H. 0.2 M. XO4-. 1. 0.1 M. Done. One sentence. It's easy. BA2+. 0.2 M. XO4-. 0.4 M. There are 2 XO4-. 2. CA2+. 0.2 M. XO4-. 2. 0.2 M. A, B, C are very easy. D is also 1. But the calculation formula is a bit complicated. Because it is related to the specific volume of C%. There are 2 ways to calculate D. We can calculate normally or apply this formula. It's quite strange. We calculate this formula directly. We calculate Cm of H2O4. Cm is 10. D is C%. Divided by M. 10 D C%. Divided by M. This is the formula for calculating Cm. 10. D. D is 1. 5. 0.3. Divided by C%. Cm of H2O4 is 98. 10. 1. 5. 0.3. Divided by M. 9. 2 M. 9. 2 M. 9. 2 M. H2O4 is 18.4. HO4 minus 10 M. HO4 minus M. H2O4 minus M. HO4 minus M. E. A, B, C, D is the number of molecules in a molecule Now it's E E is different E When we mix different molecules we have to calculate the mole number Here is 200 ml and here is 300 ml We have to calculate the mole number of each molecule We do it from the mole number E mole of MgSO4 which is small but large is 12 We divide it by MgSO4 which is 24 plus 96 which is 120 which is 0.1 mole This is the mole number Now we calculate the mole number of Al2SO4 3 times This is 342 34.2 divided by 342 which is 0.1 mole This is the mole number which is M Now we can write it down We don't have to write it down Let's do it This guy will create Mg2+, the mole number of Mg2+, which is 0.1 and the mole number of Al2SO4 which is 0.1 This guy will create Mg3+, the mole number of Mg3+, which is 2 which is 0.2 the mole number of Al2SO4 which is 0.3 We're not done yet Let's look at the whole There are only 3 guys Mg2+, Al3+, Al2SO4 Now we calculate the mole number Mg2+, which is 0.1 divided by 200 which is 300 Cmn divided by 0.1 divided by 0.5 which is 0.2M Al3+, which is 0.2 divided by 0.5 which is 0.4M Al3+, which is 0.1 divided by 0.3 which is 0.4 0.4 divided by 0.5 which is 0.8M That's how we know we do and mix it up Next, F There are only 3 guys RonTechLaurie and the whole The video is quite long Let's try to see it all If we leave it, it will be out of shape If you choose, it will be out of shape F is 50mL I remind you If you receive a document We join the group to help you study Currently, in the group, there are documents of the first chapter There are 6 chapters This is chapter 64 and chapter 136 Answer the question F is mixed up Now we have to calculate the mole and then write the ratio PaOH2L mole 0.2 0.05 0.2 0.05 0.01 mole NHNO3 0.1 0.15 0.015 mole If we study after the simple liquid flow equation we will do the simple liquid flow equation But now we haven't studied Especially that chapter later We write the equation NHNO3 plus PaOH2L equals PaNO3 2L plus water Equal to 2.1 Here we have to 0.015 0.01 2.1 0.015 0.0075 0.00 0.075 So the compound liquid flow equation is PaNO3 2 times 0.0075 mole BA0.075 and BA0.075 are both 0.025 mol Now we can calculate the temperature Let's calculate the mol The temperature of BA0.075 and BA0.075 Let's calculate the temperature of BA0.075 and BA0.025 Divide by the total mol The total mol is 0.2 0.1 divided by 0.2 by 0.05 0.05 It's a bit confusing, but I haven't taught you yet The third mol Divide by 0.0075 Divide by 0.2 0.015 Divide by 0.2 by 0.0075 0.0075 mol The last mol 0.005 divided by 0.2 by 0.025 0.025 mol We've done this one The third mol Assic I will take another piece of paper and divide it to make it easier Coba Acid and Bay Calcium and Calcium and Acid HSO4 minus is Acid HSO4 minus and H24 minus This is the H root of Acid This is the Calcium H2 PO4 minus PO4 minus is Bay PO4 minus NH3 is Bay NH3 S2 minus S2 minus is Bay Na plus Na plus Calcium N3 plus Cl minus CO3 minus CO3 minus is Bay CO3 Acid NH4 plus NH4 plus is Acid NH4 plus H minus Calcium H minus Label HSO4 minus Acid H4 So the output will be SO4, two letters, it loses the letter H This guy gets H, so it becomes H3O So now it is the output that has the H The corresponding is NH4+, plus water It's the same, it is NH3 This guy added H3O to the equation H3O+, so this guy is the assist This is how we write it Continue with PO4-3, write it down PO4-3 plus water We write the whole equation Then it will be HBO4-2 plus OH- He added H here H is the flight Like this NH3 plus water NH3 plus water, so it becomes NH4+, plus OH- NH3, NH4+, so he added H So it becomes the flight This guy wrote it himself Now we write the equation We can't write the equation We can't add or subtract Now we write the equation H2BO4- plus water The equation is giving and receiving H If it receives H, it becomes H3BO4 H plus OH If it receives H, it becomes the flight If H2BO4- plus water If it receives H, it becomes HBO4- plus H3O If it receives H, it becomes H This is the way to write the equation Now there is a part of the equation Before doing this, let's do the test part There are a lot of exercises This book has a total of 120 sentences There are theoretical exercises, self-examination exercises, full-time exercises, etc. Now let's continue with the test part In this test part, I will add the electric power conservation in here If we watch this video, we will understand the conservation of electricity The term is not electricity conservation Electricity conservation is acid-bicarbonate This is acid, this is bicarbonate This is salt, this is salt This is alcohol It is not acid-bicarbonate, not electricity conservation The term is not electricity conservation The more ions, the better The less ions, the worse HF is weak HCL is strong HPR is strong HA is strong This guy is the weakest His concentration is the lowest His ions are the least That's why HF is the least The scientific formula is certain When electricity produces Fe3 and SO4- This guy has 3, this guy has 2 We add up We get Fe2, SO4-3 Add up too much Fe2, SO4-3 The following case is not electricity conservation As I said, in the case of cutting salt or snake scale Snake scale is not electricity conservation Snake scale The following is the concentration of electrolytes The concentration of electrolytes is acid, now salt This guy, this guy is not electrolyte Sugar is not electrolyte Acid The following is the concentration of strong electrolytes Strong electrolytes include strong acid, strong Fe3 And salt Strong electrolytes, strong acid, strong Fe3 This guy is weak Fe3, ignore it Weak acid, ignore it Alkohol, ignore it Alkohol is not electrolyte The following is the concentration of strong acid, strong salt Salt, salt, salt This guy is salt, salt, salt Wrong The main problem Use CH3SOH first CH3SOH, it separates CH3SO- and H CH3SOH- and H And it also has it So this is the name of the god Kobe There Then, the video is very long I will go through and guide the electricity conservation power as promised Electricity conservation power Electricity conservation power will guide us From the 57th to the 60th The 60th is a different calculation Then from the 57th Dung Yich Yich This guy I called the A, B, C This is the electricity conservation power Electricity conservation power is the total mole The total mole of the magnetic field Equal to the total mole of the negative magnetic field The total mole of the magnetic field and the total mole of the negative magnetic field G2 plus and Mg2 plus So now it's A1 plus B2 A1 plus B2 Equal to C1 plus D2 C1 plus D2 Do not enter this mark Here is the electricity conservation power That's it Then If this is written as a formula, what is it? We understand 1 times mole A plus Plus 2 times mole Mg2 plus Total Total by 1 times mole C minus Plus 2 times mole R4 minus 2 This is the electricity conservation power Then Then the 58th continues like this This guy Now I write the total area The total area is the total mole Area 2 times mole Mg2 plus Plus 1 times mole K plus All the area to the mole The mole of the negative magnetic field 1 times mole of the negative magnetic field Plus 2 times mole R4 minus 2 Wait for me to calculate R4 minus 2 Then you will understand The total mole is 0.1 This is 0.1 0.25 Subtract this formula out It's 0.1 and 0.25 So it's 0.075 Question B That means we press it ourselves Here is the teacher That is the question B Let's see if the answer is correct Or we press it The teacher wants to be quick Question 57 The answer has all the details for us Let's not worry Sometimes we don't understand what we learn Ask the teacher Question 57, right? B, right Question 58, B Question 59 Okay, question 59 is the same First A triangle Let's choose the answer first Because it's a triangle These guys don't match Let's choose the answer C3 and OH- Because these two guys are incompatible with these So we choose these two answers The rest is CL- and OH- These two answers are correct But let's save the details These two guys are all 1 So we get 0.01 times 1 Square plus 0.02 times 2 Equals 0.02 times 1 Plus this guy is 1 A times 1 Then we subtract this The total here is 0.05 So it's not 0.03 It's not 3A, not 0.03 Or we press the calculator So it's A There are two values left So it's not 0.03 The last question is related to salt Have you called the epidemic? This is 3+. NH4+, FE3+, CL-, OH- We have to find X first Then calculate the area 0.02 times 1 Plus X times 3 FE3+, equals 0.01 times 1 Plus 0.02 times 2 Now we will find X After X, we will find salt Then X will be equal to Let me take a look X equals This side is 0.05 So X is equal to 0.01 X is equal to 0.01 Now press salt Total salt, we add it 0.02 times this guy is 18 Plus X is 0.01 FE is 56 Plus 0.01 times 35.5 Plus 0.02 times 4 is 96 Then the answer is 3.195 Let's see if there is an answer here 3.195 This is the answer for B There This is a lot of practice This system is a total of 120 sentences For the topic mainly theoretical or not After we finish this, we make sure we understand Then This is a topic-type system So we can use it for all three books Any book we use is fine So The topic today is topic 3 There are 4 topics left Topic 7 is all Now in the group The learning support group There is a file for us We print the document as we do This is already printed This is the file for us to print 64 pages Print this one 64 pages 166 pages Printed We can look at it I will end the video here