noc20_me45_lec14

IIT Kanpur July 201
20 followers
Dec 2, 2023
Hello and welcome to the 14th lecture of Machining Science course. So, we were discussing the tool
wear and tool life. We have seen that Taylor's tool life equation which is one of the very basic
tool life equation, equation on the tool life that relates the tool life with the parameter
like cutting velocity. And then we said that the extended tool life equation, Taylor's extended
tool life equation relates the tool life not only to the cutting velocity but also to the feed and
the depth of cut. Well and also we said that on the tool life maximum effect will be of the cutting
velocity followed by feed and then by the depth of cut. Because we have seen that experimentally
the powers of the velocity is more than the power 1 by n which is more than 1 by n1 and
which is more than 1 by n2. This is how if we see this, this is how we have said in the last
lecture. Now, let us see the factors or the variables affecting the tool life. These are
the 5 factors which are the cutting conditions, tool geometry, tool material, work material and
the cutting fluid. They affect the tool life and how they affect the tool life we will discuss it
right now. Effect of tool geometry, let us say rake angle. Increasing the rake angle we know
that reduces the cutting force and the cutting temperature. Therefore, it increase the resulting
in the increased tool life. This we have discussed while discussing the selection of the rake angles.
So, increasing the rake angle it will reduce the force, it will reduce the cutting temperature and
the tool life will be increased and the vice versa. However, for large rake angle the edge
is weakened resulting in the increased wear due to chipping of the cutting edge and the tool
life decreases. So, therefore there is an optimum value of the rake angle at which the tool life
will be maximum. Increased wear is also due to larger temperature since the tool becomes thinner
and the area available for heat conduction or the material available for the heat conduction
will be less. This also we have discussed earlier. These conditions give an optimum rake angle which
gives the maximum tool life as I said. Higher is the strength of workpiece material,
lower is the value of optimum rake angle it is obvious. If the strength of the workpiece
material is higher in that case the force required will be more and then it will reduce the tool
life. Now, the flank angle increasing the flank angle reduces rubbing between the tool and the
workpiece and hence it improves the tool life. So, while increasing the flank angle as we have
discussed earlier also the cutting angle reduces and the tool again weakens that reduces the tool
life. Optimum value of flank angles is also affected by the feed rates. Higher is the feed
rate, lower is the optimum value of the flank angle. The flank angle therefore should be low
if higher feed values are used. So, these are the recommendations which are theoretically as
well as experimentally obtained. For example, here if you see these are the curves that I have shown
it earlier that is this is a similar curve to the tool life and the cutting velocity we have
seen earlier. So, here what is shown here that since on the tool life we have the effect of
cutting velocity, feed and the together they will actually increase the cutting temperature.
So, here what is shown is that the relationship of the cutting temperature theta on the tool life
jointly I mean which combiningly saying that this is the effect of the cutting speed,
feed and the depth of cut because in terms of temperature all these three will enhance
the temperature if they are increased. Now, here what is shown that the rake angle
as we are increasing the rake angle initially the tool life is increasing, but then afterwards it
decreases because the tool gets weakened and if we say that this is the harder material than this,
than this, this is the strength of material in that case the optimum value of the rake
angle will be lower. So, earlier conclusion that we have made that optimum value of flank
angle is also affected by the feed rates. And here we have said that higher is the
strength of work material, lower is the value of the optimum rake angle. So,
this is what is shown here. Now, here it is the flank angle. So,
as we are increasing the flank angle initially the tool life is increasing as we said because
the rubbing is less, but afterwards the tool again weakens and the tool life decreases.
And as the feed is increasing let us say this is the maximum feed, this is lower than F1,
this is lower than F3. So, with that the flank optimum flank angle that will be getting should
be less. So, if F1 is more than F2 then more than F3 then the optimum value of the flank angle will
be less, delta 1 will be less than delta 2 than delta 3. Now, on the tool and the work material
the phenomena is very interesting in the sense that tool work material must be at least 35 to
58 percent harder than the work material. This has been established by the experiments
and the high strain rate of deformation and the elevated temperature of the work material
complicate the situation. In a way that with the increase in machining speed the temperature of
both the tool and the work material increases. Machining zone temperature is increasing as
the machining progresses as the cutting velocity increases. This is increasing the temperature of
the tool and the work material resulting in a lowered effective hardness of the tool.
Unfortunately, the expected fall in the hardness in the work material is neutralized or compensated
by the higher rate of deformation. See, you understand that higher rate of deformation
means what? High resistance to the deformation that is high strength. So, what is happening is
that more the plastic deformation is imparted to the workpiece more will be the resistance. So,
the apparent strength of the workpiece is increasing as if. So, therefore, at a higher
temperature the tool and the workpiece material both are getting the same temperature, but the
tool is thermally getting softened because the thermal softening of the workpiece does not happen
because of the strain hardening. Because the more deformation more plastic deformation is
imparted to the workpiece, workpiece is having the reaction in terms of increased strength.
So, therefore, the tool wears out more and therefore, the 30 percent to 58 percent
more hardness is required for the tool material than the workpiece material.
In general, harder the work material higher will be the tool wear rate and lower will be the tool
life. This is understood. This I already said to you earlier. Now, let us see the effect of the
cutting fluid. Cutting fluids are primarily used for decreasing the cutting temperature and the
chip tool interface friction. So, there are two functions of the cutting fluid to decrease the
temperature and to decrease the friction between the chip and the rake face of the tool.
They also serve to keep the workpiece cool to avoid thermal expansion, provide a rust proof
layer on the finished surface and remove chips from the machining area. These are known.
Cutting fluid should have high specific heat and good thermal conductivity. This is also understood
so that it actually takes out the heat from the machining zone. A chemical constituent
form weak junction so that build up age does not happen because build up age happens because of the
nascent surfaces. If the nascent surfaces are covered with a layer, they cannot get welded
and therefore, there is no build up age formation. So, this is the mechanism.
Should have a low viscosity because it has to penetrate. If it is very thick,
very high viscosity in that case, it cannot penetrate the machining zone and small molecular
size so that it can penetrate easily, non-corrosive and inexpensive. At a very high speed,
coolant is inefficient because it cannot get enough time to reach the machining zone and also
it cannot get into the machining zone because of that wedge which is formed by the tool and
the workpiece and the chip. At that wedge, when the cutting fluid is passed at a high speed,
it actually creates a hydrodynamic force and because of the hydrodynamic force it actually
that force forces back the cutting fluid from the zone and it does not
permit the cutting fluid to reach. So, these are the two reasons basically because of which the
at higher speed the tool, the cutting fluid is not very effective.
Let us give you some numerical examples. These are self-explanatory. Now, this is the
practical implementation of whatever we have learned. For example, tool life test in turning
yields the following data. At this speed, the tool life is given. At another speed,
the tool life is given. You have to determine the N and C values of the Taylor's tool life equation.
Based on your equation, compute the tool life for a speed of 90 meter per minute and the speed
corresponding to a tool life of 20 minute. So, you can see that you can get two equations,
Taylor's tool life equation VT to the power N is equal to C, V given, T given. So, N and C
from these two equations you can find out. So, you solve these two equations simultaneously,
you find out the values of N and C which are constants. Once you found out the values of N
and C, then for 90 meter per minute you can find out 90 meter per minute here V,
T is unknown to the power C which is which you found out, sorry N which is which you found out
is equal to constant C which is here. So, from here you can find out what is the value of T.
So, similarly you can find out the V if the T is given, same principle because it is said in the
C the speed corresponding to a tool life of 20 minute. So, tool life is given, you have to find
out the speed. Similar to that you can find out the V is 83.4. Second example is the turning
test have resulted in 1 minute tool life for a cutting speed of 4 and 20 minute tool life
at a speed of 2 meter per second. Find the N and C values. It is like in the previous case
for data 1 we have the tool life T and then the C is this. For data V is equal to 2 meter per
second which is 120 meter per minute you find out you have you have the C and the you have the C.
So, find out that V T to the power N is equal to this C. So, find out what is the value of the N
from here by solving this equation. So, at V is equal to 1 which is 60 meter per minute because
the in the V T to the power N is equal to C V velocity is given in meter per minute
and tool life is given in minute. So, here you put this value V here 60,
T is unknown, C and N, N and C will be known find out what is the value of the T.
So, this is easy once you know the once you know the formula V T and formula is very simple V T
to the power N is equal to C which is constant. Third example is a very similar one in a
production turning operation the work part of 125 millimeter in diameter and 300 millimeter long
a feed rate of this is used in the operation. If cutting speed is 3 meter per second the tool
must be changed every 5 work parts, but if cutting speed is 2 meter per second the tool can be used
to produce 25 pieces between the tool changes determine the Taylor's tool life equation.
So, you have to find out the T m here you are converting that into the minute
find out and then for the second case you also find out the T.
Now, the V is given convert it to meter per minute because as I said V has to be in meter
per minute and then you put it in the Taylor's tool life equation with the V and T known.
Then within with these two equations two unknown N and C you can always find out the two unknown
value solving the equation in the way it is shown here. So, these are the simple examples
and you can implement the tool life equation and whatever we have learned earlier in the form of
numerical examples. This is the machine tool that is known I am not going into very details
of this. So, my idea is to study something or to discuss something which is let us say
these are the holding of the workpiece particularly in the turning this is the example of the boring.
So, I am not going into details because these are simple things and you must have seen that
you must have gone through in your curriculum. This is the shaping and planing example. So,
whatever we have said I am just giving you the glimpse of those operations. This is the
shaping and planing machine here is the drill and the entire specification of the drill here
and you remember I told you about the point angle this is the point angle between the two lips.
This is how the drilling is made this is either through hole this is the through hole or it is
a blind hole it does not go up to the full depth. This is the machining operation which is the
rimming, tapping, counter boring just have a glimpse of it and this is the milling where we
have the peripheral milling, face milling, slab milling, slotting, end milling. We have the up
milling and down milling you know that up milling means the direction of the milling cutter rotation
and the feed are different down milling is the same and these are the specifications that what
happens in case of down milling or what happens in the case of the up milling. These things are
common thing here there is no science behind this so you can see this. These are the milling
this is milling machines example horizontal and vertical depending on the axis of the milling
cutter. If it is horizontal it is a horizontal milling machine if the axis is vertical so it
is a vertical milling machine. This is broaching example I have told you broaching in the very
beginning that by that you can make a internal slots or external slots with high accuracy.
So, this is the broaching operation and this is the particular specification that the good
surface finish is obtained by broaching. These are the internal broaching this kind of slots
you can make in the as the internal broaching. Now our idea will be to also discuss the abrasive
machining processes because here this abrasive machining processes differ from the single point
cutting tool or the multi point cutting tool like drilling or milling in the way that here we have
a lot of tools lot of single point tools and each grain is supposed to be a tool.
Now hard particles like Al2O3, B4C, silicon carbide they actually abrade the softer material
and that is why the machining process which use the hard materials like aluminum oxide,
boron carbide or silicon carbide they are called the abrasive processes or abrasive machining
processes you know that. Now the material removal by action of hard abrasive particles
usually in the form of bonded wheel. This is particularly in case of grinding
generally used as finishing operations and in grinding although there is a material removal
but in other abrasive machining for example in honing or lapping the material removal is minimum
but it basically uses as the finishing operation so that the surface finish can be enhanced.
Now the abrasive machining processes the grinding wheel has the lot of abrasive particles as I said.
Abrasive particles accomplish cutting bonding material holds particle in place and establishes
shape and structure of the wheel. So the grinding wheel parameters are basically there are 5
parameters on which the grinding wheel performance will depend. This is the abrasive
type of material type of abrasive material, grain size, wheel grade, wheel structure and the bonding
material. So depending on what kind of abrasive material we are using either Al2O3 or silicon
carbide or diamond depending on what kind of grain size we are using rough bigger grain size or
medium grain size or smaller grain size. What is the wheel grade? Grade is the strength of
the bonding material what kind of grade we are using depending on that we will have the
grinding wheel as the hard or the soft. Wheel structure what is the gap or the void
between the grains in the grinding wheel or the bonding material either it is a vitrified bond or
it is a shellac or it is a resinoid or it is a rubber or it is a metal depending on that you
will have the performance of the grinding wheel defined. Let us see for example the type of
abrasive material it can have either Al2O3 designated by A or silicon carbide C or the
cubic super abrasives are there, there are cubic boron nitride, diamond etc.
So Al2O3 used for grinding steel, ferrous alloys, bronze and other high strength materials
whereas silicon carbide which is more expensive used for grinding brittle materials cast iron,
brass, aluminum and hard alloys and the carbides. By aluminum do not get surprised because on the
top of aluminum there is an aluminum oxide which is very hard. Aluminum itself may not be a hard
material but on that aluminum oxide that is very difficult to grind and the carbides which are
very hard. So grain size is expressed in terms of the sieve number, sieve number is Sn which
corresponds to the number of openings per linear inch. So if you have a linear inch let us say
here there is 1 inch by 1 inch, 1 inch by 1 inch. So how many openings you have that is the sieve
number. And that from that sieve number you can find out the diameter of an abrasive grain
which will be 0.6 divided by Sn mind it it is given in inch. So always you have to convert
into micron or millimeter. The largest the size of the grain the more will be the material removal
you understand that. Bigger grains will remove more material and surface finish will be worse.
So the sieve numbers are given in this way. These are internationally accepted 10 to 24
for example these are the coarse or the bigger grains 30 to 60 sieve number will be medium grain,
70 to 80 will be fine grains and 220 to 600 is very fine grain. So you understand that more the
sieve number since it is inversely proportional less will be the diameter of the abrasive grain
meaning that for example if it is a 600 sieve number, 600 sieve number will be a very fine grain
because it is given by 0.6 by Sn which is 0.6 by 600 in inch. So you can convert that into micron
it will be a very small or very small particle small grain. Similarly the grade indicates the
strength of the binding material as I said when the work material is hard the grains wear out
easily and the sharpness of the cutting edges is quickly lost this is known as the wheel glazing
meaning that if you have a hard workpiece material and a hard wheel.
So since the wheel is hard and the workpiece is hard the wheel grain I mean the grains on
the surface of the wheel will be very quickly worn out and since the wheel is hard those worn
out grains will not be dislodged from the surface of the wheel. So they will stay mean
worn out grains will stay and that will rub more and consume more power this is called the wheel
glazing because the wheel surface then will look like a glazed surface because they are covered
with the worn out grains which are dull grades they rub more and remove less material consume
more power. So wheel glazing is not desirable it should be resharpened and that layer has to be
removed by the diamond pin as you understand that. So to avoid this problem a soft wheel should be
used because in the case of soft wheel if the workpiece material is hard the wheel the wheel
grains will be worn out but they will be dislodged because the wheel is soft.
And why we want the grains to be dislodged because behind the dislodged grain
there will always be sharp grains so those sharp grains will come out and they will remove more
material they will consume less power. So here the specification of the grade is that A to H
these are also internationally accepted A to H is the soft wheel J to P is the medium wheel
and Q to Z is a hard wheel. Now the structure like in the case of the milling cutter
between the milling teeth milling cutter teeth we have the void or the space and though that
space is for accommodating the chips. So similarly in the grinding wheel between
the grains there should be some space that will accommodate the chips and if the space is very
small then the small chips anyway in grinding the chips are very small those small chips will get
into the small space between the grains and they will stay there they will not be able to come out
and then we say that wheel is loaded there is a loading of the wheel phenomena.
Like in the case of glazing the loaded wheel will not be cutting effectively it will rub more and it
will consume more power because on the surface of the wheel then we will have the chips embedded.
So therefore we should not allow the wheel loading and as soon as the wheel loading
takes place as soon as we see that the power is increasing or the force is increasing in that case
we have to remove that layer by the resharpening of the or it is called the wheel dressing by
dressing of the wheel we have to remove that layer. If the voids are too small as I said
then the loading will happen so here there are 17 structures 0 to 16 dense to open 0 is most dense
most densely packed that means the voids or the space is very small and 16 is the open or in
between you have the for example 10 so 10 will be not very open not very dense.
So recommendations are that for hard workpiece material we should have the closed structure
and for open structure means the voids are relatively large and grains are relatively
small so that you understand that if the grains are small then the closed structure will be there
and recommended when clearance for chips must be provided. Dense structure so we said that
open structure should be provided so open structure should be recommended for chips
for clearance for the chips. Dense structure means voids are relatively small and grains are larger
recommended to obtain better surface finish and dimensional control.
So for dense we mean to say by 12, 13, 14 and so on up to 16 so those are for better finish
and for more dimensional accuracy. Bonding materials as I explained it to you that there
are vitrified bond, resinoid, silicate, shellac, rubber bonds, metallic bonds and each of them has
is indicated by an alphabet. Vitrified bond is V which is strong rigid which are commonly used.
Resinoid provides the shock absorption and elasticity they are strong.
Silicate provides softness grains dislodge quickly. Shellac is used for making thin but
strong wheels possessing some elasticity and the rubber bonds they are making therefore making
flexible wheels. For example if the wheel is used for parting of a very thick or high diameter
of the workpiece so it has to penetrate the workpiece and it should have some flexibility
because it vibrates and if it is very rigid and strong this will break. So therefore this
flexibility is given by the rubber bonds and some sort of elasticity is given by the resinoid also.
Metallic bonds are exclusively used for the diamond wheels.
Now you must have seen that each of this is characterized by a number and a letter.
For example abrasive material here we have an alphabet next to that we have a letter
next to that we have an alphabet again then again a letter and so on. So therefore
the grinding wheel specification a standard grinding wheel marking system used to designate
abrasive type, grit size, grade structure and bond will be given by this way. So here
we can see that this is the abrasive type this is the size of the abrasive grain this is the grade
this is the structure and this is the bond. So when you buy or purchase the abrasive wheel
nobody will tell you that what is the grade actually what is the it will be said like this
only thing is that should be some kind of an manufacturer s code in the beginning and at the
end and otherwise these 5 will signify that what is the grinding wheel specification.
Once again abrasive type this is the grain size this is the grade this is the structure and this
is the bond kind of bond. Also provides for additional identifications for use by grinding
wheel manufacturers as I said that these will be the manufacturers code plus these 5 specifications.
So some of the other things in grinding which are very important and which have which needs
some discussion that we will do in the next class. Thank you very much for your attention.
