[Vật lý 10]CÂN BẰNG VẬT RẮN- Moment Lực (Chương 5 Bài 13 Phần 4)

Thầy Linh Toán Lý
25 người theo dõi
2 Lượt xem video·15 thg 11, 2023
Hello, I'm going to continue with the
equation number 4 equation number 4 in
the school 5 is about the power of the
force and the equation of the equation of the
equation number 4 it has content like this
the light bodies abvc
on this board
the light bodies abvc are connected to each other
and connected to the wall thanks to the
boards
at A applies a straight force
with a mass of 1000 newton
find the unit force of the bodies
if alpha is equal to 30 degrees and
beta is equal to 60 degrees
alpha is equal to 30 degrees
beta is equal to 60 degrees
the unit force of the body is the unit force
of the body on the body on the body is
abvc
the content of our lesson
is just how much it is also quite
simple
now we go to the content of this
equation, that is, the
abvc is the wall
abvc is the two light bodies
it is said to be hard and light and it is
connected to each other
and this is it
so you see that in this case
people give the angle alpha is equal to 30 degrees
alpha is equal to 30 degrees
60 degrees
so it is clear that the triangle
abc is the triangle square at A
square at A
now calculate the unit force it
applies to the body abvc
so you see that
the object that people put on this
A, the forces applied to A
the forces
applied to the point A
means that the force P Pho
the force P Pho
the second is the unit force of the
body abvc is the force of the body
abvc
here is the body abvc
tb
it's simple
and of course
this force P Pho
affects this body abvc is a force
ttc
that is, it is directed to the point C
, it is tc, it is directed to the point B, it is
ttb and you see that
if you believe it,
you can apply the angle of the triangle to
this point A
.
I
will
be very simple
now you see
now
and the
diagonal is in the direction of A
and the center of it here
is of course it is
equal to the weight of B
so
the system
of this object is due to that according to the
Newton's law 2
according to Newton's law 2, the forces
applied to this
force
applied to this point A is the force P Pho
then tb
tb
tc
tb
tc
