4-Felder-Tafel bei der "Bedingten Wahrscheinlichkeit" | Mathe by Daniel Jung
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Well, it should be B, B crosswise.
As a result, the probability of P of B would be 0.5, the probability of P of B crosswise would be 0.5, the probability of P of A would be 0.5,
the probability of P of A crosswise would be 70%, the probability of P of A crosswise would be 30% and here the control, the two added must result in 100%, the two also and that fits, it is 1 for 100%.
If you now have the tree diagram next to it, then you can better assign where the non-bindings are, where the overall probability is for A or A crosswise, B or B crosswise.
Here you cannot read the conditional probabilities, for this it is important to either apply the sentence from Bayes or to go into the tree diagram.