[Vật lý 11,12] Con Lắc Đơn Dao Động Trong Điện Trường (Chủ đề 3 - Phần 1)

Thầy Linh Toán Lý
25 người theo dõi
#ly11 #lylop11 #vatly11 #ly11thaylinh #thaylinhmp #ly11ketnoi #ly11chantroi #ly11canhdieu #ketnoitrithuc #chantroisangtao #canhdieu #lylop12 #vatlylop12
#conlacdon #conlac
Hello everyone, now let's go back to
the
theme that the unit is moving in an
electric field environment on the board is the
calculator, then this calculator has
a content like this, here you read the
topic, let me tell you a unit
moving in an electric field
with a length l is equal to 50 cm
is equal to 10 grams
this ball is calculated with the
calculation point is equal to 5 but for 10
times 6
and put in an even electric field with a
straight line down and the force of the
electric field is 10.4 volts per meter
people say g is equal to 10 meters on the
normal line, people say b is equal to 3.14
people ask me to find the
moving force of this unit,
then people give out four
answers. The first answer is 1.4 seconds, the
second answer is 1.99 seconds, the
third answer is 0.58 seconds and the
fourth answer is 1.15 seconds. This is also
the
calculation of Vinh Phuc School in 2016
2017
before solving this equation,
I will
tell you in detail that the
structure that was built on
the
speed is called the speed of expression
when the unit is placed in an
environment that does not have the electric field,
then you know that if the unit is placed
in the air or in the air in an
environment that does not have the external force
, it only has the effect of the
speed of expression, that is, the effect of the
force of the earth, then in the case
that it has the effect of the electric field,
the speed is no longer g, but
the speed is g
, it can be greater than g or
smaller than g. If the speed is
greater than g, it corresponds to the
case that this unit has an additional
effect of a force to push the
ball down below. In this case,
I will draw a model here.
If our m is here,
it has a magnitude of m and the
magnetic field is q.
The magnetic field of the electric field is
straight up and down like this.
You can see that when the
heavy object is placed here, of
course, first of all, it has the effect of
the
magnetic field.
The second one, this magnetic field is
the magnetic field due to the magnetic field
in the electric field, it has the effect of
the force of the electric field and the force of the electric
field is calculated as F by the
rule of A. If the rule is square,
you can see that F is equal to
A, but if the rule is square,
F and A are the same. In this case,
it is because it is the force.
It is the same as the force of the
electric field.
So I see that this heavy object
is now
the effect of two forces, the
magnitude and the force of the electric field.
And at the equal position, I
see that the string
has a force of T,
it is equal to these two
forces. So we have T
at the equal position
at the equal position of the string,
you have T,
it's equal to T, it's equal to
B with FFQ, right?
T is equal to T with FQ,
T is up
and B and FQ are down and
these two are equal to each other.
It turns out that T is equal to B plus
FQ. So you can see that
this is B,
it is equal to M,
so we have the speed now
not
more
B
