Đồ thị động năng theo độ biến dạng - thầy VNA

Hello everyone! Today I will continue to give you a sentence about the energy of energy, good and difficult And it is also at a very light level, not too difficult for you to think about This is a sentence I quote from the science of breaking the rule of the teacher If you are in the science of the teacher, you will participate in many sentences like this And even better and more difficult, this sentence is still the basic level of the teacher The sentence is as follows 1. There is a spring that is placed where there is a G by Pi bottle The unit is the meter on the string of bottles, which is about 10 2. It is stimulated to move in a straight line 3. The momentum of the momentum according to the deformation of the spring As shown in the figure, find the speed of the object when the deformation is A A is a position on the screen, but at this time our momentum is 3 over 4 of the magnetic field The momentum of the magnetic field is 4 over 4 of the magnetic field At this time, compared to the deformation of A, the momentum is 3 over 4 of the magnetic field I will explore later, I will explore the data of this sentence This is a very important point At this point, the momentum is 0 and the deformation is 1 At this point, the momentum is 0 That position is the momentum of 0 The momentum of 0 can only be at the edge But what edge is it? With a spring hanging straight, there will be two states The state of tension and the state of friction The distance between the two states is in the natural position Is the position of the deformation of 0 The deformation of 0 is the boundary between tension and friction You look at this point Does this point look like a circle? Is the deformation of 0 And you know, this is our natural position Is the boundary between tension and friction And you know, with a spring hanging straight The friction direction will be more Tension direction, friction time will be more So look at this, here is the boundary So the upper part, the boundary over there Will be the friction spring time The whole process from here to here is the friction spring And the process from here to here is the spring At this point is the most friction spring At this point, the spring is not deformed At this point, the spring is the most deformed And it is at the edge, the momentum is 0 This position is the momentum of 0 and the deformation is 1 The momentum of 0 is at the edge And we just proved that the most friction is at the edge And we give the deformation degree as 1 This is the most deformation degree at the edge Is the most friction That is how many? A minus delta L0 Delta L0 is the deformation degree at the equilibrium position Here, ok The deformation at the edge is A minus delta L0 Is the most deformation degree And the unit is cm We already have a equation for A and delta L0 Next, you use another position Is this position on the screen Right? This position is the deformation degree by 0 The deformation degree by 0 is at what position? The deformation degree by 0 is at the natural position Right? At the natural position, what does the equation give you? The momentum at this time is 1 over 4 of the magnitude The momentum is 1 over 4, the force is 3 over 4 At this position, our momentum is 1 over 4 of the magnitude The deformation degree is 3 over 4 of the force Right? When the deformation degree is 3 over 4 of the force Our x is what you think? Plus minus a plus 3 over 2 The body is hiding the minus Because at the natural position is the magnetic field with the direction down Right? At this time, our x is minus a plus 3 over 2 Done? Because the force is 3 over 4 of the force And at the natural position, our x is minus delta L0 It's easy, right? At the natural position, the deformation degree is minus delta L0 So you can get here We have our A Delta L0 Right? Delta L0 by a plus 3 over 2 Done? From the above equation and the below equation We will get what? We will get A and delta L0 This is a pretty good question From a teacher Admin Tran Vinh He made a pretty good question Right? You know Huy Tai He made a pretty good question And Tran Vinh He is Huy Tai's friend He made a pretty good question about this Right? He has a lot of good admin channels And a lot of creativity He is his old student He made a lot of good questions So I hope After these videos If we have any good ideas You can send them to me I will save them and read your name I'm very proud Alright Let's continue We will get here What is it? Delta L0 and A Do we have two hidden equations? Let's replace the numbers One is the original Our A is 2 delta L0 Divide by 3 And this one is directly for delta L0 Done? Let's press delta L0 Divide by 2 divided by 3 Divided by 1 Right? Ok Our delta L0 is here It is equal to 6.46 It's close 6.5 cm Delta L0 is G Divide by omega square But you have to remember Pay attention Change it to the teacher's meter Right? It is omega G is the square Divide by the answer of 100 Ok? Take G and divide by 100 It is omega square Omega The number is a bit odd Don't mind it It is 12.35 12.4 Just make a circle Radian on the string See? I have omega I have delta L0 Of course I have A See? Write it here It will be nice What is our A? With delta L0 It is 6.5 See? Our A 6.5 divided by 3.2 See? 7.5 It is quite nice A is 7.5 cm Ok That's it You have to find the speed When the degree changes to A The degree changes to A The letter A Actually doesn't have much meaning Right? Look at this line Right? This line is very important At this line At that point is the intersection The momentum is 3.4 of what? Maximum Right? Ok The momentum is 3.4 of the momentum You can calculate V By adding the opposite sign Right? 3 divided by 2 of V Ok? The momentum is 3.4 of the momentum V is 3.2 of V Do we have V is omega divided by A? 3 divided by 2 Omega is 12.4 Omega divided by A is 7.5 Right? Ok Our speed now It falls to about 80.54 cm per second 80.54 cm per second That's it This is the result of the math This question is still 4 lines Right? And in the development of the teacher There are many more questions Many better questions like this Right? This question is still a normal level question You guys I just do it carefully Detailed is possible But the question about the degree of deformation According to the momentum It's very good See? Better than this question I've been live-streaming You can see it Right? This question is still normal Ok Alright Mechanical engineering science Conquering high-end and high-end sentences Will be unveiled by the VNA teacher On July 25, 2021 Please register to be loved soon 99k