Chữa FULL Đề Luyện tốc độ số 05 - Thầy VNA

it's B, it can't be C, how many are always 3 points and P not consecutively, so m and P are here, I can't give P three points in a row, so I'm wrong, right? Okay, I called it it's about X, it's always like that, the points that have the same magnitude must be So, Mn minus Np is 8 Mn is lambda divided by 2 plus 2x Mn is this part From here to here is lambda divided by 2 Next, Np is lambda divided by 2 minus 2x Is it done? 8 OK What is x now? This one is over 4x x is 2 Is it done? x is 2 Note that the magnitude of Np is 2a Is it done? This point has magnitude of a Which is the distance between lambda and 12 One point is the distance between lambda and 12 That's the magnitude of Np So, we get lambda is 24 C is correct This one is easy OK? Easy, right? 37 is C This one is B So, let's go to the 3 hardest questions today Here The 3 hardest questions 38, 39 and 40 How many times have you seen this? See? How many times have you seen this? The magnitude of the magnitude of the momentum According to the magnitude of the pullback The magnitude of the momentum is the individual delta L The magnitude of the pullback is the individual magnitude of x Here, the magnitude of the momentum is in the ocean See? Here, the magnitude of the pullback is 0 It's in the equilibrium position Here, the magnitude of the pullback is 0 It's in the natural position See? Here is After passing through the natural The magnitude of the pullback increases to this value It's in the parallel See? There are 4 special positions of our horizontal oscilloscope Parallel, parallel, equilibrium and natural See? I can see all of them In the parallel The magnitude is 0.8 So, 0.8 of us Is the individual A minus delta L0 The first equation See? Next, look at this In the natural position And which position Our pullback has the same value Ok? The pullback has the same value That is, the absolute value of x must be the same And the absolute value of x must be the same That is, the equilibrium position is about the same Do you understand the problem? This is the equilibrium position This is the natural position Ok? From here to here It's delta L0 See? Because our equilibrium is naturally delta L0 Does it make sense? Look at this These two points give the same pullback Right? These two points give the same pullback That is, the same oscilloscope on the horizon It has the same pullback The same pullback The same absolute value of x Because the pullback is the absolute value of x The same absolute value of x That is, the equilibrium position is about the same Do you understand? The equilibrium position is about the same Ok? Look at this One position is natural One position In these two positions One position is natural One position is opposite You see? It has to be balanced That is, how to balance delta L0 See? These are two positions that are balanced Give the same pullback One position is natural This position is balanced Do you understand? At this time, the amplitude is 2 delta L0 Do you understand? The amplitude here is 2 delta L0 This position The position that is not natural The amplitude is 2 delta L0 So it is always 2.4 times K divided by 2 delta L0 Do you understand? The momentum has a large degree of hardness Divided by the degree of variation So here Here the degree of variation is 0 But here the degree of variation is 2 delta L0 Do you understand? It has to correspond to the natural position through the equilibrium position Do you understand? Then give the same absolute value of x At this time, there is the same pullback And the total amplitude at that time The amplitude must be compared to the natural Do you understand? The amplitude is delta L0 But the degree of variation is 2 delta L0 So I just divide it down So I always take 0.8 divided by 1.2 Is 2 times 3 That is A minus delta L0 Divide by delta L0 I take 0.8 divided by 1.2 Done? So you always get the relationship between A and delta L0 What is it? Here you get 5 delta L0 Do you understand? By 3A Is it correct? Let's change the symbol 5 delta L0 divided by 3A On the other hand, look at this It is asked for the magnitude of the object Look carefully The magnitude of the object Our A max Divided by omega square A That's why you finished using the equation You can't use it anymore I have to replace it with this I use this Do you understand? Look carefully Our A This is omega square Our A 5 divided by 3 delta L0 Omega square 5 divided by 3 Delta L0 is G divided by omega square That's it The good thing is You have to solve it But you can't solve it Look at this question In this question, you can solve it A divided by 5 divided by 3 delta L0 I replace it Delta L0 is G divided by omega square I accidentally subtracted omega square It is 5 divided by 3 of G G divided by 10 OK 5 divided by 3 is 10 G divided by 10 Don't try to do it How much is it? 16.67 Do you understand? Meter on the tape Here The answer C is correct Do you understand? See? Sometimes you do it You try to do it Right? But it's not like that The question is solving this problem Do you understand? Here, many people don't look at the question Just try to calculate delta L0 Calculate A Can't calculate anymore Done? This question is difficult Let's try The last two questions are questions 3, 9 and 40 Do you understand? These are the more difficult questions Level must be high Do you understand? The equation must be high It's so illogical How can it be illogical? Here 39 Three lines AB, CD, EF are parallel OK CD is between AB and EF Then there is a line 28 There is a middle line OK Here, I draw it These three are not even People don't talk about evenness You often get confused It's very even Do you understand? It's in the middle Not in the middle It's in the middle Do you understand? It's in the middle AB, CD, EF Do you understand? 39, Gia Bao Bao Za A Vuong Ly A OK Kang Red Doi Song Gau A You often get confused OK Let's continue O, Y, Z are the points of the middle line Do you understand? O Y Z Do you understand? A, W, E, W are the same The line will be Lambda 6 CD has 7 extreme points EF has 3 extreme points Do you understand? We can't have many EZ lines Here, these are the same as the line 28 This is 14 Do you understand? These lines are the same as the line 28 OK It looks like Japanese Done So We solve EF first EF has 3 extreme points There is already a large part that does not cut And there will be a large part that cuts again, which is part 1 Part 1 is cut, then part minus 1 is cut on this side So that's enough for 3 points Our part 2 will not cut anymore Our part 2 will not cut EF anymore So that means F's part F's part is larger than 1 and smaller than 2 Part 1 and F are fine Note that part 1 and F are fine But part 2 cannot be cut If part 2 cuts EF, then EF has 5 large parts And what is F's part? A is FA Part is the distance FA divided by FB divided by lambda Then move lambda to 2 sides Is 6, this is 12 F's part is FA divided by FB divided by lambda OK? Then this can be pulled in a bit FA is this part FA here FA, FB FB is I FA is used by Pythagoras From here, it is 6 Smaller than this This is I Plus 28 Minus FE, FB Is I Smaller than 12 OK 1 equation Next, do the same with point D At this time, on our CD, there are 7 large parts This line is so ugly On our CD, there are 7 large parts Then it will have a 3-cut line 3-cut line Because if it is 3-cut, the other side is also 3-cut From minus 3 to 3, there are 7 large parts Right? So the last part that cuts D is part 3 And the part that does not cut D is part 4 Part 4 does not cut D Because part 4 cuts D, both sides have 9 large parts While only 7 large parts So the part of D is larger than or equal to 3 But must be smaller than 4 Larger than 3, but must be smaller than 4 Then the part of D is DA divided by DB divided by Lambda DA divided by DB divided by Lambda 6x3 is 18, 6x4 is 24 Done? Here you call again Call again There is no way Right, you have to call again Call, this is X See, this is DA, 18 See, X DA is X squared plus 28 squared There, and DB is X Smaller than 24 Oh my God See, oh my God, a series of equations Look a little bit to see if we have any unused elements Easy, our Easy is E-X Easy is E-X Oh my God, it's so confusing Oh my God, wait a minute Let's see if there are any unused elements Equal to the length of 28 parallel lines This one is just solved, but it's so difficult Now, our Easy cannot be evaluated Wait a minute I forgot how to solve this question, but I just solved this question It's hard, it's hard Here we will X-Y Easy is X-Y Ah, E-X Easy is E-X Come here, I will solve it See, I will solve this one Continue, it's not difficult Here, you solve it You put the equal sign here Put the equal sign here, solve E How much smaller, how much smaller Here is the same, see Don't have to think too much I thought I had to combine the two Find the sum of X and Y